An array is monotonic if it is either monotone increasing or monotone decreasing.
An array A
is monotone increasing if for all i <= j
, A[i] <= A[j]
. An array A
is monotone decreasing if for all i <= j
, A[i] >= A[j]
.
Return true
if and only if the given array A
is monotonic.
Example 1:
Input: [1,2,2,3]
Output: true
Example 2:
Input: [6,5,4,4]
Output: true
Example 3:
Input: [1,3,2]
Output: false
Example 4:
Input: [1,2,4,5]
Output: true
Example 5:
Input: [1,1,1]
Output: true
Note:
1 <= A.length <= 50000
-100000 <= A[i] <= 100000
解题
两种 CPP 的方法耗时几乎相等,方法 1 依照错误先行的逻辑处理,在特定情况下会更快,方法 2 为参考用例
CPP 版本
class Solution {
public:
bool isMonotonic(vector<int>& A) {
if (A.size() < 2) {
return true;
}
bool increase = false;
bool decrease = false;
for (int i = 1; i < A.size(); i++) {
if (A[i] > A[i - 1]) {
increase = true;
}
if (A[i] < A[i - 1]) {
decrease = true;
}
if (increase && decrease) {
return false;
}
}
return true;
}
};
JS 版本
/**
* @param {number[]} A
* @return {boolean}
*/
var isMonotonic = function(A) {
if (A.length < 2) {
return true;
}
let increase = false;
let decrease = false;
for (let i = 1; i < A.length; i++) {
if (A[i] > A[i - 1]) {
increase = true;
}
if (A[i] < A[i - 1]) {
decrease = true;
}
if (increase && decrease) {
return false;
}
}
return true;
};
全局“与”方案
class Solution {
public:
bool isMonotonic(vector<int> A) {
bool inc = true, dec = true;
for (int i = 1; i < A.size(); ++i)
inc &= A[i - 1] <= A[i], dec &= A[i - 1] >= A[i];
return inc || dec;
}
};
全局“与”方案+错误先行
class Solution {
public:
bool isMonotonic(vector<int> A) {
bool inc = true, dec = true;
for (int i = 1; i < A.size(); ++i)
{
inc &= A[i - 1] <= A[i];
dec &= A[i - 1] >= A[i];
if (!(inc || dec)) {
return false;
}
}
return true;
}
};