Given a string s and a string t, check if s is subsequence of t.
You may assume that there is only lower case English letters in both s and t. t is potentially a very long (length ~= 500,000) string, and s is a short string (<=100).
A subsequence of a string is a new string which is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (ie, "ace"
is a subsequence of "abcde"
while "aec"
is not).
Example 1:
s = "abc"
, t = "ahbgdc"
Return true
.
Example 2:
s = "axc"
, t = "ahbgdc"
Return false
.
Follow up:
If there are lots of incoming S, say S1, S2, … , Sk where k >= 1B, and you want to check one by one to see if T has its subsequence. In this scenario, how would you change your code?
Credits:
Special thanks to @pbrother for adding this problem and creating all test cases.
Runtime: 120 ms, faster than 12.75% of C++ online submissions for Is Subsequence.
Memory Usage: 14.8 MB, less than 100.00% of C++ online submissions for Is Subsequence.
class Solution {
public:
bool isSubsequence(string s, string t) {
if (s.length() > t.length()) {
return false;
}
if (s.empty() || t.empty()) {
return true;
}
int pos = 0;
for (int i = 0; i < t.length(); i++) {
if (s[pos] == t[i]) {
pos++;
}
if (pos == s.length()) {
return true;
}
}
return false;
}
};