Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number.
The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2.
Note:
Your returned answers (both index1 and index2) are not zero-based.
You may assume that each input would have exactly one solution and you may not use the same element twice.
Example:
Input: numbers = [2,7,11,15], target = 9
Output: [1,2]
Explanation: The sum of 2 and 7 is 9. Therefore index1 = 1, index2 = 2.
/**
* @param {number[]} numbers
* @param {number} target
* @return {number[]}
*/
var twoSum = function(numbers, target) {
const len = numbers.length;
let i = 0;
let j = len - 1;
let sum = 0;
while(i < len) {
sum = numbers[i] + numbers[j];
if (sum === target) {
return [i + 1, j + 1];
}
if (sum < target) {
i++;
} else {
j--;
}
}
};