public void merge(int[] nums1, int m, int[] nums2, int n) { // two get pointers for nums1 and nums2 int p1 = m - 1; int p2 = n - 1; // set pointer for nums1 int p = m + n - 1; // while there are still elements to compare while ((p1 >= 0) && (p2 >= 0)) // compare two elements from nums1 and nums2 // and add the largest one in nums1 nums1[p--] = (nums1[p1] < nums2[p2]) ? nums2[p2--] : nums1[p1--]; // add missing elements from nums2 System.arraycopy(nums2, 0, nums1, 0, p2 + 1);///上面减1了,移动元素的个数。// 作者:LeetCode// 链接:https://leetcode-cn.com/problems/merge-sorted-array/solution/he-bing-liang-ge-you-xu-shu-zu-by-leetcode/ }
System.arraycopy(nums2, 0, nums1, m, n);//移动元素的个数Arrays.sort(nums1);