1141. 查询近30天活跃用户数
活动记录表:Activity
+---------------+---------+
| Column Name | Type |
+---------------+---------+
| user_id | int |
| session_id | int |
| activity_date | date |
| activity_type | enum |
+---------------+---------+
该表是用户在社交网站的活动记录。
该表没有主键,可能包含重复数据。
activity_type 字段为以下四种值 ('open_session', 'end_session', 'scroll_down', 'send_message')。
每个 session_id 只属于一个用户。
请写SQL查询出截至 2019-07-27(包含2019-07-27),近 30天的每日活跃用户数(当天只要有一条活动记录,即为活跃用户)。
查询结果示例如下:
Activity table:
+---------+------------+---------------+---------------+
| user_id | session_id | activity_date | activity_type |
+---------+------------+---------------+---------------+
| 1 | 1 | 2019-07-20 | open_session |
| 1 | 1 | 2019-07-20 | scroll_down |
| 1 | 1 | 2019-07-20 | end_session |
| 2 | 4 | 2019-07-20 | open_session |
| 2 | 4 | 2019-07-21 | send_message |
| 2 | 4 | 2019-07-21 | end_session |
| 3 | 2 | 2019-07-21 | open_session |
| 3 | 2 | 2019-07-21 | send_message |
| 3 | 2 | 2019-07-21 | end_session |
| 4 | 3 | 2019-06-25 | open_session |
| 4 | 3 | 2019-06-25 | end_session |
+---------+------------+---------------+---------------+
Result table:
+------------+--------------+
| day | active_users |
+------------+--------------+
| 2019-07-20 | 2 |
| 2019-07-21 | 2 |
+------------+--------------+
非活跃用户的记录不需要展示。
/
select
activity_date day,
count(distinct user_id ) active_users
from
Activity
group by
activity_date
having
datediff('2019-07-27',activity_date )<30
为什么是<30而不是等于,因为包含07-27,所以除了今天还有29天。如果不包含27号就是等于30了
select activity_date day, count(distinct user_id) active_users
from activity
where activity_date > date_sub('2019-07-27', interval 30 day)
and activity_date <= '2019-07-27'
group by activity_date