二叉树中序遍历递归

难度中等

题目描述

给定一个二叉树的根节点root,返回它的中序 遍历。

解题思路

递归遍历:左-中-右

Code

  1. /**
  2. * Definition for a binary tree node.
  3. * public class TreeNode {
  4. * int val;
  5. * TreeNode left;
  6. * TreeNode right;
  7. * TreeNode() {}
  8. * TreeNode(int val) { this.val = val; }
  9. * TreeNode(int val, TreeNode left, TreeNode right) {
  10. * this.val = val;
  11. * this.left = left;
  12. * this.right = right;
  13. * }
  14. * }
  15. */
  16. class Solution {
  17. List<Integer> ans = new ArrayList<>();
  18. public List<Integer> inorderTraversal(TreeNode root) {
  19. if (root == null) {
  20. return ans;
  21. }
  22. inTraversal(root);
  23. return ans;
  24. }
  25. public void inTraversal(TreeNode cur) {
  26. if (cur == null) {
  27. return;
  28. }
  29. inTraversal(cur.left);
  30. ans.add(cur.val);
  31. inTraversal(cur.right);
  32. }
  33. }