451.根据字符串频率排序

/*** @param {string} s* @return {string}*/var frequencySort = function (s) {let map = new Map();for (let i of s) {map.set(i, (map.get(i) || 0) + 1);}const list = [...map.keys()];list.sort((a, b) => map.get(b) - map.get(a));const sb = [];const size = list.length;for (let i = 0; i < size; i++) {const ch = list[i];for (let j = 0; j < map.get(ch); j++) {sb.push(ch);}}return sb.join('');};
