全排列

image-20210504092842700.png

  1. /**
  2. * @param {number[]} nums
  3. * @return {number[][]}
  4. */
  5. Array.prototype.contains = function(num){
  6. for(let i=0;i<this.length;i++){
  7. if(this[i]===num){
  8. return true;
  9. }
  10. }
  11. return false;
  12. };
  13. var permute = function(nums) {
  14. let res = [];
  15. let track = [];
  16. backtrack(nums,track);
  17. return res;
  18. function backtrack(nums,track){
  19. if(nums.length===track.length){
  20. let newTrack = [];
  21. Object.assign(newTrack,track)
  22. res.push(newTrack);
  23. return;
  24. }
  25. for(let num of nums){
  26. if(track.contains(num)){
  27. continue;
  28. }
  29. track.push(num);
  30. backtrack(nums,track);
  31. track.pop();
  32. }
  33. }
  34. };

子集

image-20210504093621622.png
这个需要剪枝:
dfs2.png

  1. /**
  2. * @param {number[]} nums
  3. * @return {number[][]}
  4. */
  5. var subsets = function(nums) {
  6. let res = [];
  7. let track = [];
  8. trackback(nums,track,0);
  9. return res;
  10. function trackback(nums,track,start){
  11. let newTrack = [];
  12. Object.assign(newTrack,track);
  13. res.push(newTrack);
  14. for(let i=start;i<nums.length;i++){
  15. track.push(nums[i]);
  16. trackback(nums,track,i+1)
  17. track.pop();
  18. }
  19. }
  20. };

二叉树最小高度

image-20210504094011605.png

  1. 输入:root = [3,9,20,null,null,15,7]
  2. 输出:2
/**
 * Definition for a binary tree node.
 * function TreeNode(val, left, right) {
 *     this.val = (val===undefined ? 0 : val)
 *     this.left = (left===undefined ? null : left)
 *     this.right = (right===undefined ? null : right)
 * }
 */
/**
 * @param {TreeNode} root
 * @return {number}
 */
var minDepth = function (root) {
    if (!root === true) {
        return 0;
    }
    let queue = [];
    let depth = 1;
    queue.push(root);
    while (queue.length !== 0) {
        // 踩坑:这里queue.length要另外写在外面,要是写在循环里是动态改变的,最终结果始终输出1
        let ql = queue.length;
        for (let i = 0; i < ql; i++) {
            let cur = queue.shift();
            if (cur.left === null && cur.right === null) {
                return depth;
            }
            if (cur.left !== null) {
                queue.push(cur.left);
            }
            if (cur.right !== null) {
                queue.push(cur.right);
            }
        }
        depth++;
    }
    return depth;
};