剑指 Offer 30. 包含min函数的栈
难度简单
定义栈的数据结构,请在该类型中实现一个能够得到栈的最小元素的 min 函数在该栈中,调用 min、push 及 pop 的时间复杂度都是 O(1)。
示例:
MinStack minStack = new MinStack(); minStack.push(-2); minStack.push(0); minStack.push(-3); minStack.min(); —> 返回 -3. minStack.pop(); minStack.top(); —> 返回 0. minStack.min(); —> 返回 -2.
提示:
- 各函数的调用总次数不超过 20000 次
/*** initialize your data structure here.*/var MinStack = function() {//x_stack用来存储新的数据//min_stack用来存储每一位数据对应的状态下的最小值this.x_stack = []this.min_stack = [Infinity]};/*** @param {number} x* @return {void}*/MinStack.prototype.push = function(x) {this.x_stack.push(x)this.min_stack.push(Math.min(this.min_stack[this.min_stack.length-1],x))};/*** @return {void}*/MinStack.prototype.pop = function() {this.x_stack.pop()this.min_stack.pop()};/*** @return {number}*/MinStack.prototype.top = function() {return this.x_stack[this.x_stack.length-1]};/*** @return {number}*/MinStack.prototype.min = function() {return this.min_stack[this.min_stack.length-1]};/*** Your MinStack object will be instantiated and called as such:* var obj = new MinStack()* obj.push(x)* obj.pop()* var param_3 = obj.top()* var param_4 = obj.min()*/
