- 先验分布:关于参数
的先验估计
%0A#card=math&code=p%5Cleft%28%20%5Ctheta%20%5Cright%29%0A)
- 后验分布:在给出数据
后,关于参数
的估计
%20%3D%5Cfrac%7Bp%5Cleft(%20%5Ctheta%20%2Cx%20%5Cright)%7D%7Bp%5Cleft(%20x%20%5Cright)%7D%3D%5Cfrac%7Bp%5Cleft(%20x%5Cmid%20%5Ctheta%20%5Cright)%20%5Ccdot%20p%5Cleft(%20%5Ctheta%20%5Cright)%7D%7B%5Cint%7B%5Ctheta%7D%7Bp%5Cleft(%20x%5Cmid%20%5Ctheta%20%5Cright)%20%5Ccdot%20p%5Cleft(%20%5Ctheta%20%5Cright)%20%5Cmathrm%7Bd%7D%5Ctheta%7D%7D%0A#card=math&code=p%5Cleft%28%20%5Ctheta%20%5Cmid%20x%20%5Cright%29%20%3D%5Cfrac%7Bp%5Cleft%28%20%5Ctheta%20%2Cx%20%5Cright%29%7D%7Bp%5Cleft%28%20x%20%5Cright%29%7D%3D%5Cfrac%7Bp%5Cleft%28%20x%5Cmid%20%5Ctheta%20%5Cright%29%20%5Ccdot%20p%5Cleft%28%20%5Ctheta%20%5Cright%29%7D%7B%5Cint%7B%5Ctheta%7D%7Bp%5Cleft%28%20x%5Cmid%20%5Ctheta%20%5Cright%29%20%5Ccdot%20p%5Cleft%28%20%5Ctheta%20%5Cright%29%20%5Cmathrm%7Bd%7D%5Ctheta%7D%7D%0A)
例子
已知盒内4球,有红白两色,取一次后放回,连取4次,有3红1白
我们设盒内红球有 个,白球有
个,其中
.
设取出红球个数为 个,那么有:
%20%3DC%7B4%7D%5E%7Bx%7D%5Ccdot%20%5Cleft(%20%5Cfrac%7B%5Ctheta%7D%7B4%7D%20%5Cright)%20%5Ex%5Cleft(%20%5Cfrac%7B4-%5Ctheta%7D%7B4%7D%20%5Cright)%20%5E%7B4-x%7D%0A#card=math&code=p%5Cleft%28%20x%5Cmid%20%5Ctheta%20%5Cright%29%20%3DC%7B4%7D%5E%7Bx%7D%5Ccdot%20%5Cleft%28%20%5Cfrac%7B%5Ctheta%7D%7B4%7D%20%5Cright%29%20%5Ex%5Cleft%28%20%5Cfrac%7B4-%5Ctheta%7D%7B4%7D%20%5Cright%29%20%5E%7B4-x%7D%0A)
如果 ,那么:
%20%3D%5Cfrac%7B1%7D%7B64%7D%5Ctheta%20%5E3%5Cleft(%204-%5Ctheta%20%5Cright)%0A#card=math&code=p%5Cleft%28%20x%3D3%5Cmid%20%5Ctheta%20%5Cright%29%20%3D%5Cfrac%7B1%7D%7B64%7D%5Ctheta%20%5E3%5Cleft%28%204-%5Ctheta%20%5Cright%29%0A)
对于不同的 ,有:
%20%26%3D0%5C%5C%0A%09p%5Cleft(%20x%3D3%5Cmid%20%5Ctheta%20%3D1%20%5Cright)%20%26%3D%5Cfrac%7B3%7D%7B64%7D%5C%5C%0A%09p%5Cleft(%20x%3D3%5Cmid%20%5Ctheta%20%3D2%20%5Cright)%20%26%3D%5Cfrac%7B16%7D%7B64%7D%5C%5C%0A%09p%5Cleft(%20x%3D3%5Cmid%20%5Ctheta%20%3D3%20%5Cright)%20%26%3D%5Cfrac%7B27%7D%7B64%7D%5C%5C%0A%09p%5Cleft(%20x%3D3%5Cmid%20%5Ctheta%20%3D4%20%5Cright)%20%26%3D0%5C%5C%0A%5Cend%7Baligned%7D%0A#card=math&code=%5Cbegin%7Baligned%7D%0A%09p%5Cleft%28%20x%3D3%5Cmid%20%5Ctheta%20%3D0%20%5Cright%29%20%26%3D0%5C%5C%0A%09p%5Cleft%28%20x%3D3%5Cmid%20%5Ctheta%20%3D1%20%5Cright%29%20%26%3D%5Cfrac%7B3%7D%7B64%7D%5C%5C%0A%09p%5Cleft%28%20x%3D3%5Cmid%20%5Ctheta%20%3D2%20%5Cright%29%20%26%3D%5Cfrac%7B16%7D%7B64%7D%5C%5C%0A%09p%5Cleft%28%20x%3D3%5Cmid%20%5Ctheta%20%3D3%20%5Cright%29%20%26%3D%5Cfrac%7B27%7D%7B64%7D%5C%5C%0A%09p%5Cleft%28%20x%3D3%5Cmid%20%5Ctheta%20%3D4%20%5Cright%29%20%26%3D0%5C%5C%0A%5Cend%7Baligned%7D%0A)
由贝叶斯公式可知:
%20%3D%5Cfrac%7Bp%5Cleft(%20x%3D3%5Cmid%20%5Ctheta%20%5Cright)%20%5Ccdot%20p%5Cleft(%20%5Ctheta%20%5Cright)%7D%7B%5Csum%7B%5Ctheta%20%3D0%7D%5E4%7Bp%5Cleft(%20x%3D3%5Cmid%20%5Ctheta%20%5Cright)%20%5Ccdot%20p%5Cleft(%20%5Ctheta%20%5Cright)%7D%7D%0A#card=math&code=p%5Cleft%28%20%5Ctheta%20%5Cmid%20x%3D3%20%5Cright%29%20%3D%5Cfrac%7Bp%5Cleft%28%20x%3D3%5Cmid%20%5Ctheta%20%5Cright%29%20%5Ccdot%20p%5Cleft%28%20%5Ctheta%20%5Cright%29%7D%7B%5Csum%7B%5Ctheta%20%3D0%7D%5E4%7Bp%5Cleft%28%20x%3D3%5Cmid%20%5Ctheta%20%5Cright%29%20%5Ccdot%20p%5Cleft%28%20%5Ctheta%20%5Cright%29%7D%7D%0A)
如果按正常情况,我们认为 $\theta $ 是服从均匀分布的,即 %3D1%2F5%2C%5C%2C(i%3D0%2C%5Cldots%2C4)#card=math&code=p%28%5Ctheta%3Di%29%3D1%2F5%2C%5C%2C%28i%3D0%2C%5Cldots%2C4%29).
那么
%20%3D%5Cbegin%7Bcases%7D%0A%09%5Cfrac%7B1%7D%7B5%7D%5Crightarrow%200%2C%5Cqquad%20i%3D0%5C%5C%0A%09%5Cfrac%7B1%7D%7B5%7D%5Crightarrow%20%5Cfrac%7B3%7D%7B46%7D%2C%5Cqquad%20i%3D1%5C%5C%0A%09%5Cfrac%7B1%7D%7B5%7D%5Crightarrow%20%5Cfrac%7B16%7D%7B46%7D%2C%5Cqquad%20i%3D2%5C%5C%0A%09%5Cfrac%7B1%7D%7B5%7D%5Crightarrow%20%5Cfrac%7B27%7D%7B46%7D%2C%5Cqquad%20i%3D3%5C%5C%0A%09%5Cfrac%7B1%7D%7B5%7D%5Crightarrow%200%2C%5Cqquad%20i%3D4%5C%5C%0A%5Cend%7Bcases%7D%0A#card=math&code=p%5Cleft%28%20%5Ctheta%20%5Cright%29%20%3D%5Cbegin%7Bcases%7D%0A%09%5Cfrac%7B1%7D%7B5%7D%5Crightarrow%200%2C%5Cqquad%20i%3D0%5C%5C%0A%09%5Cfrac%7B1%7D%7B5%7D%5Crightarrow%20%5Cfrac%7B3%7D%7B46%7D%2C%5Cqquad%20i%3D1%5C%5C%0A%09%5Cfrac%7B1%7D%7B5%7D%5Crightarrow%20%5Cfrac%7B16%7D%7B46%7D%2C%5Cqquad%20i%3D2%5C%5C%0A%09%5Cfrac%7B1%7D%7B5%7D%5Crightarrow%20%5Cfrac%7B27%7D%7B46%7D%2C%5Cqquad%20i%3D3%5C%5C%0A%09%5Cfrac%7B1%7D%7B5%7D%5Crightarrow%200%2C%5Cqquad%20i%3D4%5C%5C%0A%5Cend%7Bcases%7D%0A)

但我们也可以认为:盒子里没有红球和白球的概率是极小的,大概率是红球白球一样多,于是我们可以认为 #card=math&code=p%28%5Ctheta%20%29) 的先验分布为:
%20%3D%5Cbegin%7Bcases%7D%0A%090%2C%5Cqquad%20i%3D0%5C%5C%0A%09%5Cfrac%7B1%7D%7B4%7D%2C%5Cqquad%20i%3D1%5C%5C%0A%09%5Cfrac%7B1%7D%7B2%7D%2C%5Cqquad%20i%3D2%5C%5C%0A%09%5Cfrac%7B1%7D%7B4%7D%2C%5Cqquad%20i%3D3%5C%5C%0A%090%2C%5Cqquad%20i%3D4%5C%5C%0A%5Cend%7Bcases%7D%0A#card=math&code=p%5Cleft%28%20%5Ctheta%20%5Cright%29%20%3D%5Cbegin%7Bcases%7D%0A%090%2C%5Cqquad%20i%3D0%5C%5C%0A%09%5Cfrac%7B1%7D%7B4%7D%2C%5Cqquad%20i%3D1%5C%5C%0A%09%5Cfrac%7B1%7D%7B2%7D%2C%5Cqquad%20i%3D2%5C%5C%0A%09%5Cfrac%7B1%7D%7B4%7D%2C%5Cqquad%20i%3D3%5C%5C%0A%090%2C%5Cqquad%20i%3D4%5C%5C%0A%5Cend%7Bcases%7D%0A)
那么我们在此先验分布之上建立的后验分布为:
%20%3D%5Cbegin%7Bcases%7D%0A%090%5Crightarrow%200%2C%5Cqquad%20i%3D0%5C%5C%0A%09%5Cfrac%7B1%7D%7B4%7D%5Crightarrow%20%5Cfrac%7B3%7D%7B62%7D%2C%5Cqquad%20i%3D1%5C%5C%0A%09%5Cfrac%7B1%7D%7B2%7D%5Crightarrow%20%5Cfrac%7B32%7D%7B62%7D%2C%5Cqquad%20i%3D2%5C%5C%0A%09%5Cfrac%7B1%7D%7B4%7D%5Crightarrow%20%5Cfrac%7B27%7D%7B62%7D%2C%5Cqquad%20i%3D3%5C%5C%0A%090%5Crightarrow%200%2C%5Cqquad%20i%3D4%5C%5C%0A%5Cend%7Bcases%7D%0A#card=math&code=p%5Cleft%28%20%5Ctheta%20%5Cright%29%20%3D%5Cbegin%7Bcases%7D%0A%090%5Crightarrow%200%2C%5Cqquad%20i%3D0%5C%5C%0A%09%5Cfrac%7B1%7D%7B4%7D%5Crightarrow%20%5Cfrac%7B3%7D%7B62%7D%2C%5Cqquad%20i%3D1%5C%5C%0A%09%5Cfrac%7B1%7D%7B2%7D%5Crightarrow%20%5Cfrac%7B32%7D%7B62%7D%2C%5Cqquad%20i%3D2%5C%5C%0A%09%5Cfrac%7B1%7D%7B4%7D%5Crightarrow%20%5Cfrac%7B27%7D%7B62%7D%2C%5Cqquad%20i%3D3%5C%5C%0A%090%5Crightarrow%200%2C%5Cqquad%20i%3D4%5C%5C%0A%5Cend%7Bcases%7D%0A)

观察这张图其实很有意思,尽管摸出了3个红球,但后验分布还是认为有两个红球的概率最大,和我们日常经验更为趋近——即使2红2白也是有可能摸出3个红球的,一次的发生可能是偶然因素。
绘图的MATLAB代码为:
clc,clearx=0:4;y=[1/5,1/5,1/5,1/5,1/5];y1=[0,3/46,16/46,27/46,0];y2=[0,1/4,1/2,1/4,0];y3=[0,3/62,32/62,27/62,0];figurehold onarea(x,y,'FaceColor',[0.7 0.7 0.7],'EdgeColor','k','FaceAlpha',0.5)area(x,y1,'FaceColor',[0.5 0.9 0.6],'EdgeColor',[0 0.5 0.1],'FaceAlpha',0.5)legend('Prior ','Posterior')figurehold onarea(x,y2,'FaceColor',[0.7 0.7 0.7],'EdgeColor','k','FaceAlpha',0.5)area(x,y3,'FaceColor',[0.5 0.9 0.6],'EdgeColor',[0 0.5 0.1],'FaceAlpha',0.5)legend('Prior ','Posterior')
