5697. 检查二进制字符串字段

  1.       class Solution {
  2.           public boolean checkOnesSegment(String s) {
  3.               int count1 = 0, count0 = 0;
  4.               for (int i = 0; i < s.length(); i++) {
  5.                   if (s.charAt(i) == '1')
  6.                       count1++;
  7.                   if (s.charAt(i) == '0')
  8.                       count0++;
  9.               }
  10.               if (count1 == 1 )
  11.                   return true;
  12.               if (count0 <= 1)
  13.                   return true;
  14.               if (count1 == 0)
  15.                   return false;
  20.               int count = 0;
  21.               int low = 0, high = 0;
  22.               while (low < s.length()) {
  23.                     if (s.charAt(low) == '1') {
  24.                         for (high = low + 1; high < s.length(); high++) {
  25.                             if (s.charAt(high) != '1')
  26.                                 break;
  27.                         }
  28.                     }
  29.                   if (high - low >= 1) {
  30.                       count++;
  31.                       low = high;
  32.                   } else {
  33.                       ++low;
  34.                   }
  35.               }
  37.               if (count == 1)
  38.                   return true;
  39.               return false;
  40.           }
  41.       }