/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode() {} * TreeNode(int val) { this.val = val; } * TreeNode(int val, TreeNode left, TreeNode right) { * this.val = val; * this.left = left; * this.right = right; * } * } */class Solution { public List<List<Integer>> zigzagLevelOrder(TreeNode root) { if (root == null) return new ArrayList(); List<List<Integer>> ans = new ArrayList<>(); Deque<TreeNode>[] stack = new Deque[2]; stack[0] = new LinkedList<>(); stack[1] = new LinkedList<>(); int current = 0; int next = 1; stack[current].add(root); List<Integer> list = new ArrayList<>(); while (!stack[0].isEmpty() || !stack[1].isEmpty()) { TreeNode node = stack[current].pop(); list.add(node.val); if (current == 0) { if (node.left != null) { stack[next].push(node.left); } if (node.right != null) { stack[next].push(node.right); } } else { if (node.right != null) { stack[next].push(node.right); } if (node.left != null) { stack[next].push(node.left); } } if (stack[current].isEmpty()) { ans.add(list); list = new ArrayList<Integer>(); current = 1 - current; next = 1 - next; } } return ans; }}