1796. 字符串中第二大的数字
class Solution {
public int secondHighest(String s) {
List<Integer> list = new ArrayList<>();
for (char c : s.toCharArray()) {
if (c >= '0' && c <= '9')
list.add(c - '0');
}
if (list.size() <= 1)
return -1;
int[] nums = new int[list.size()];
for (int i = 0; i < list.size(); i++) {
nums[i] = list.get(i);
}
Arrays.sort(nums);
if (nums[0] == nums[nums.length - 1])
return -1;
for (int i = nums.length - 2; i >= 0; i--) {
if (nums[i] != nums[i + 1])
return nums[i];
}
return -1;
}
}