
/*
设计一个递归算法,删除一个不带头结点的单链表中所有值为x的节点
分析:
首先我们要创建单链表,并赋值,然后递归去判断值,进行删除
*/
#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <stdlib.h>
struct Link
{
int value;
struct Link *next;
};
void deleteX(Link *&p, int delNum) {//这里的第一个函数参数必须是引用值,不然会导致断链
struct Link *pre;//定义一个指针,进行删除
if (p == NULL) return;
if (p->value == delNum) {
pre = p;
p = p->next;
free(pre);
deleteX(p, delNum);
}
else
deleteX(p->next, delNum);
}
Link *create() {
struct Link *p, *rear, *head;
head = (struct Link *)malloc(sizeof(struct Link));
rear = (struct Link *)malloc(sizeof(struct Link));
head = NULL;
rear = NULL;
int value;
printf("请输入链表各节点的值,以9999结束:");
scanf("%d", &value);
while (value != 9999) {//依次创建节点
p = (struct Link *)malloc(sizeof(struct Link));//创建一个新的节点
p->value = value;
p->next = NULL;
if (head == NULL) {
rear = p;
head = p;
}
else {
rear->next = p;
rear = p;
}
scanf("%d", &value);
}
rear->next = NULL;
return head;
}
Link *create2() {
struct Link *p, *rear, *head;
head = (struct Link *)malloc(sizeof(struct Link));
head = NULL;
int value;
printf("请输入链表各节点的值,以9999结束:");
scanf("%d", &value);
while (value != 9999) {//依次创建节点
p = (struct Link *)malloc(sizeof(struct Link));
p->value = value;
p->next = NULL;
if (head == NULL) {
head = p;
}
else {
p->next = head->next;
head->next = p;
}
scanf("%d", &value);
}
return head;
}
int main() {
int delNum;
struct Link *head, *q;
head = create();
q = head;
printf("打印链表:");
while (q != NULL) {
printf("%d ", q->value);
q = q->next;
}
q = head;
printf("请输入想要删除的节点的值:");
scanf("%d", &delNum);
deleteX(q, delNum);
printf("删除后链表:");
while (q != NULL) {
printf("%d ", q->value);
q = q->next;
}
return 0;
}