题目描述
经过了前面那么多题目的历练,耐心细致在解题当中是 必不可少的品质,刚巧你们都有,你和小鱼越来越入迷。那么走向了下一个题目,这个题目好长 好长,你知道你们只要细心细致,答案总会被你们做出来的,你们开始慢慢的尝试,慢慢的猜想 ,功夫不负有心人,在你们耐心的一步步的解答下,答案跃然纸上,你俩默契一笑,相视击掌 走向了下面的挑战。格式为cyberpeace{小写的你解出的答案}
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
Solution
拿到题目,发现字符串尾巴有=
,这可能是 Base64 编码,我们在 Kali 下用
cat 007.txt | base64 -d
将其解码,得到结果:
LzExOS8xMDEvMTA4Lzk5LzExMS8xMDkvMTAxLzExNi8xMTEvOTcvMTE2LzExNi85Ny85OS8xMDcvOTcvMTEwLzEwMC8xMDAvMTAxLzEwMi8xMDEvMTEwLzk5LzEwMS8xMTkvMTExLzExNC8xMDgvMTAw
这里的字符串很规则,由{
为一组,查阅资料可知这是 Unicode 编码,我们使用 Python 脚本将其当成 ASCII 去解码:
def decode(line):
str_list = line.split(";")
str_list.pop() # delete last one element '\n'
for i in str_list:
print(chr(int(i[2:])), end="")
with open("./007-decode.txt", "r") as fp:
for line in fp:
decode(line)
运行结果如下:
LzExOS8xMDEvMTA4Lzk5LzExMS8xMDkvMTAxLzExNi8xMTEvOTcvMTE2LzExNi85Ny85OS8xMDcvOTcvMTEwLzEwMC8xMDAvMTAxLzEwMi8xMDEvMTEwLzk5LzEwMS8xMTkvMTExLzExNC8xMDgvMTAw
这可能又是 Base64 编码,我们在 Kali 将其解码:
# ~/Desktop/python via 🐍 v3.8.10
❯ py decode_007.py | base64 -d
/119/101/108/99/111/109/101/116/111/97/116/116/97/99/107/97/110/100/100/101/102/101/110/99/101/119/111/114/108/100%
这一串可能是 ASCII 编码,我们再修改上面的 Python 脚本将其解码:
def decode_first(line):
str_list = line.split(";")
str_list.pop()
for i in str_list:
print(chr(int(i[2:])), end="")
def decode_second(line):
str_list = line.strip().split("/")
str_list.pop(0) # pop front
for i in str_list:
print(chr(int(i)), end="")
with open("./007-decode2.txt", "r") as fp:
for line in fp:
decode_second(line)
结果如下:
welcometoattackanddefenceworld