smtplib - 发送邮件

1 登录认证

import smtplib
host = 'smtp.mail.qq.com'
# smtp = smtplib.SMTP(host=host, port=smtplib.SMTP_PORT)
smtp = smtplib.SMTP_SSL(host=host, port=smtplib.SMTP_SSL_PORT)  # use SSL mode, recommended
res = smtp.login('username', 'password')
if res[0] == 235:
    print('login successful!')

2 发送邮件

content_type:

• plain: 文本格式
• html: HTML格式

from email.header import Header
from email.mime.text import MIMEText
from email.mime.multipart import MIMEMultipart
from_addr = 'your@mail.com'
to_addrs = 'to@mail.com'
charset = 'utf-8'
content_type = 'plain'    # or html
body = 'your mail body'
subject = 'your mail subject'
msg = MIMEMultipart()
msg['Subject'] = Header(subject, charset)
msg['To'] = to_addrs
msg.attach(MIMEText(body, content_type, charset))
smtp.sendmail(from_addr, to_addrs, msg.as_string())

3 发送多人

msg[‘To’]部分为字符串，仅用于控制显示接收人 sendmail内部to_addrs为列表，才能发送给多人，否则只会发送给第一个

to_addrs = ['a@mail.com', 'b@mail.com', 'c@mail.com']
msg['To'] = ','.join(to_addrs)
...
smtp.sendmail(from_addr, to_addrs, msg.as_string())

4 抄送密送

抄送：发送者和其他接收者都知道抄送了谁 密送：只有发送者知道密送了谁 同样的，msg[‘Cc’]和msg[‘Bcc’]只是控制显示，是否真正发送，还要看实际传给sendmail的to_addrs列表

cc_list = ['d@mail.com']
bcc_list = ['e@mail.com']
msg['Cc'] = ','.join(cc_list)
msg['Bcc'] = ','.join(bcc_list)
smtp.sendmail(from_addr, to_addrs + cc_list + bcc_list, msg.as_string())

5 发送附件

直接使用MIMEApplication创建附件对象即可，无需区分文件类型

import os
from email.mime.application import MIMEApplication
msg = MIMEMultipart()
...
attachments = [
    'a.txt',
    'b.png',
    'c.mp3',
    'd.mp4'
]
for file in attachments:
    filename = os.path.basename(file)
    application = MIMEApplication(open(file, 'rb').read())
    application.add_header('Content-Disposition', 'attachment', filename=filename)
    msg.attach(application)
smtp.sendmail(from_addr, to_addrs, msg.as_string())