二分查找的前提
- 目标函数单调递增或递减
- 存在上下界
bounded
-
代码模板
public int binarySearch(int[] array, int target) {
int left = 0, right = array.length - 1, mid;
while (left <= right) {
mid = (right - left) / 2 + left;
if (array[mid] == target) {
return mid;
} else if (array[mid] > target) {
right = mid - 1;
} else {
left = mid + 1;
}
}
return -1;
}