@Slf4j(topic = "e")public class ForkJoinTest2 extends RecursiveTask<Long> { private Long start; // 1 private Long end; // 1990900000 // 临界值 private Long temp = 10000L; public ForkJoinTest2(Long start, Long end) { this.start = start; this.end = end; } // 计算方法 @Override protected Long compute() { ReentrantLock lock = new ReentrantLock(); //tiao Condition condition = lock.newCondition(); lock.newCondition(); if ((end-start)<temp){ Long sum = 0L; for (Long i = start; i <= end; i++) { sum += i; } return sum; }else { // forkjoin 递归 long middle = (start + end) / 2; // 中间值 ForkJoinTest2 task1 = new ForkJoinTest2(start, middle); task1.fork(); // 拆分任务,把任务压入线程队列 ForkJoinTest2 task2 = new ForkJoinTest2(middle+1, end); task2.fork(); // 拆分任务,把任务压入线程队列 return task1.join() + task2.join(); } } public static void main(String[] args) throws ExecutionException, InterruptedException { //6596 // test1(); //4872 // test2(); //160 test3(); } /** * 单线程的直接10亿累加 */ public static void test1(){ Long sum = 0L; long start = System.currentTimeMillis(); for (Long i = 1L; i <= 10_0000_0000; i++) { sum += i; } long end = System.currentTimeMillis(); System.out.println("sum="+sum+" 时间:"+(end-start)); } //最基本的forkjoin 二分查找拆分任务 //拆分任务 关键在于算法 你自己写 public static void test2(){ long start = System.currentTimeMillis(); ForkJoinPool forkJoinPool = new ForkJoinPool(); ForkJoinTask<Long> task = new ForkJoinTest2(0L, 10_0000_0000L); Long sum = forkJoinPool.invoke(task);// ForkJoinTask<Long> submit = forkJoinPool.submit(task);// 提交任务// Long sum = submit.get(); long end = System.currentTimeMillis(); System.out.println("sum="+sum+" 时间:"+(end-start)); } public static void test3(){ long start = System.currentTimeMillis(); //jdk8 stream流式计算 long sum = LongStream.rangeClosed(0L, 10_0000_0000L).parallel().reduce(0, Long::sum); long end = System.currentTimeMillis(); System.out.println("sum="+sum+"时间:"+(end-start)); }}