题目与示例
110. 平衡二叉树
给定一个二叉树,判断它是否是高度平衡的二叉树。
本题中,一棵高度平衡二叉树定义为:
一个二叉树每个节点 的左右两个子树的高度差的绝对值不超过 1 。
示例 1:
输入:root = [3,9,20,null,null,15,7]
输出:true
代码
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public boolean isBalanced(TreeNode root) {
return depth(root) != -1;
}
public int depth(TreeNode node){
if(node == null) return 0;
int leftDepth = depth(node.left);
if(leftDepth == -1) return -1;
int rightDepth =depth(node.right);
if(rightDepth == -1) return -1;
if(Math.abs(leftDepth-rightDepth)>1){
return -1;
}
return Math.max(leftDepth,rightDepth) +1 ;
}
}