题目与示例
110. 平衡二叉树给定一个二叉树,判断它是否是高度平衡的二叉树。本题中,一棵高度平衡二叉树定义为:一个二叉树每个节点 的左右两个子树的高度差的绝对值不超过 1 。
示例 1:输入:root = [3,9,20,null,null,15,7]输出:true
代码
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode() {} * TreeNode(int val) { this.val = val; } * TreeNode(int val, TreeNode left, TreeNode right) { * this.val = val; * this.left = left; * this.right = right; * } * } */class Solution { public boolean isBalanced(TreeNode root) { return depth(root) != -1; } public int depth(TreeNode node){ if(node == null) return 0; int leftDepth = depth(node.left); if(leftDepth == -1) return -1; int rightDepth =depth(node.right); if(rightDepth == -1) return -1; if(Math.abs(leftDepth-rightDepth)>1){ return -1; } return Math.max(leftDepth,rightDepth) +1 ; }}