获取(m,n)之间的素数个数

1、使用内置函数filter

def prime2(m, n):
    filter_list = filter(lambda x: not [x % i for i in range(2, x) if x % i == 0], range(m, n))
    return len(list(filter_list))
print(prime2(10, 20))

2、循环遍历

def prime(m, n):
    prime_list = []
    for i in range(m, n):
        for j in range(2, i):
            if i % j == 0:
                break
        else:
            prime_list.append(i)
    return len(prime_list)

print(prime(10, 20))