题目链接
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
// 1.之前写的,使用栈保存, 0ms,100.00%
public List<Integer> preorderTraversal1(TreeNode root) {
List<Integer> list = new ArrayList<>();
// preRoot(root, list);
if(root == null) {
return list;
}
//通过栈进行迭代
Stack<TreeNode> stack = new Stack<>();
stack.push(root);
while(!stack.isEmpty()) {
TreeNode node = stack.pop();
list.add(node.val);
if(node.right != null) {
stack.push(node.right);
}
if(node.left != null) {
stack.push(node.left);
}
}
return list;
}
//前序递归
public void preRoot(TreeNode root, List<Integer> list) {
if(root != null) {
list.add(root.val);
preRoot(root.left, list);
preRoot(root.right, list);
}
}
//中序递归
public void preRoot2(TreeNode root, List<Integer> list) {
if(root != null) {
preRoot(root.left, list);
list.add(root.val);
preRoot(root.right, list);
}
}
//后序递归
public void preRoot3(TreeNode root, List<Integer> list) {
if(root != null) {
preRoot(root.left, list);
preRoot(root.right, list);
list.add(root.val);
}
}
// 2. 0ms,100.00%
public List<Integer> preorderTraversal(TreeNode root) {
List<Integer> list = new ArrayList<>();
preRoot(root, list);
return list;
}
}