题目链接
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode() {} * TreeNode(int val) { this.val = val; } * TreeNode(int val, TreeNode left, TreeNode right) { * this.val = val; * this.left = left; * this.right = right; * } * } */class Solution { // 1.之前写的,使用栈保存, 0ms,100.00% public List<Integer> preorderTraversal1(TreeNode root) { List<Integer> list = new ArrayList<>(); // preRoot(root, list); if(root == null) { return list; } //通过栈进行迭代 Stack<TreeNode> stack = new Stack<>(); stack.push(root); while(!stack.isEmpty()) { TreeNode node = stack.pop(); list.add(node.val); if(node.right != null) { stack.push(node.right); } if(node.left != null) { stack.push(node.left); } } return list; } //前序递归 public void preRoot(TreeNode root, List<Integer> list) { if(root != null) { list.add(root.val); preRoot(root.left, list); preRoot(root.right, list); } } //中序递归 public void preRoot2(TreeNode root, List<Integer> list) { if(root != null) { preRoot(root.left, list); list.add(root.val); preRoot(root.right, list); } } //后序递归 public void preRoot3(TreeNode root, List<Integer> list) { if(root != null) { preRoot(root.left, list); preRoot(root.right, list); list.add(root.val); } } // 2. 0ms,100.00% public List<Integer> preorderTraversal(TreeNode root) { List<Integer> list = new ArrayList<>(); preRoot(root, list); return list; }}