题目链接

    1. /**
    2. * Definition for a binary tree node.
    3. * public class TreeNode {
    4. * int val;
    5. * TreeNode left;
    6. * TreeNode right;
    7. * TreeNode() {}
    8. * TreeNode(int val) { this.val = val; }
    9. * TreeNode(int val, TreeNode left, TreeNode right) {
    10. * this.val = val;
    11. * this.left = left;
    12. * this.right = right;
    13. * }
    14. * }
    15. */
    16. class Solution {
    17. // 1.之前写的,使用栈保存, 0ms,100.00%
    18. public List<Integer> preorderTraversal1(TreeNode root) {
    19. List<Integer> list = new ArrayList<>();
    20. // preRoot(root, list);
    21. if(root == null) {
    22. return list;
    23. }
    24. //通过栈进行迭代
    25. Stack<TreeNode> stack = new Stack<>();
    26. stack.push(root);
    27. while(!stack.isEmpty()) {
    28. TreeNode node = stack.pop();
    29. list.add(node.val);
    30. if(node.right != null) {
    31. stack.push(node.right);
    32. }
    33. if(node.left != null) {
    34. stack.push(node.left);
    35. }
    36. }
    37. return list;
    38. }
    39. //前序递归
    40. public void preRoot(TreeNode root, List<Integer> list) {
    41. if(root != null) {
    42. list.add(root.val);
    43. preRoot(root.left, list);
    44. preRoot(root.right, list);
    45. }
    46. }
    47. //中序递归
    48. public void preRoot2(TreeNode root, List<Integer> list) {
    49. if(root != null) {
    50. preRoot(root.left, list);
    51. list.add(root.val);
    52. preRoot(root.right, list);
    53. }
    54. }
    55. //后序递归
    56. public void preRoot3(TreeNode root, List<Integer> list) {
    57. if(root != null) {
    58. preRoot(root.left, list);
    59. preRoot(root.right, list);
    60. list.add(root.val);
    61. }
    62. }
    63. // 2. 0ms,100.00%
    64. public List<Integer> preorderTraversal(TreeNode root) {
    65. List<Integer> list = new ArrayList<>();
    66. preRoot(root, list);
    67. return list;
    68. }
    69. }