题目描述:
解析:优先级队列
class Solution {public ListNode sortList(ListNode head) {ListNode dummy = new ListNode(0);ListNode curr = dummy;PriorityQueue<ListNode> priorityQueue = new PriorityQueue<>((o1, o2) -> o1.val-o2.val);while (head != null) {priorityQueue.offer(new ListNode(head.val));head = head.next;}while (!priorityQueue.isEmpty()) {curr.next = priorityQueue.poll();curr=curr.next;}return dummy.next;}}
