1. 给定一个仅包含数字 2-9 的字符串,返回所有它能表示的字母组合。答案可以按 任意顺序 返回。
    2. 给出数字到字母的映射如下(与电话按键相同)。注意 1 不对应任何字母。
    3. 示例 1
    4. 输入:digits = "23"
    5. 输出:["ad","ae","af","bd","be","bf","cd","ce","cf"]
    6. 示例 2
    7. 输入:digits = ""
    8. 输出:[]

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    1. class Solution {
    2. List<String> result = new ArrayList<>();
    3. public List<String> letterCombinations(String digits) {
    4. if (digits == null || digits.length() == 0) {
    5. return result;
    6. }
    7. String[] numString = {
    8. "", "", "abc", "def",
    9. "ghi", "jkl", "mno",
    10. "pqrs", "tuv", "wxyz"};
    11. backTracking(digits, numString, 0);
    12. return result;
    13. }
    14. StringBuilder temp = new StringBuilder();
    15. public void backTracking(String digits, String[] numString, int num) {
    16. //遍历全部一次记录一次得到的字符串
    17. if (num == digits.length()) {
    18. result.add(temp.toString());
    19. return;
    20. }
    21. String str = numString[digits.charAt(num) - '0'];
    22. for (int i = 0; i < str.length(); i++) {
    23. temp.append(str.charAt(i));
    24. backTracking(digits, numString, num + 1);
    25. temp.deleteCharAt(temp.length() - 1);
    26. }
    27. }
    28. }