给定一个仅包含数字 2-9 的字符串,返回所有它能表示的字母组合。答案可以按 任意顺序 返回。
给出数字到字母的映射如下(与电话按键相同)。注意 1 不对应任何字母。
示例 1:
输入:digits = "23"
输出:["ad","ae","af","bd","be","bf","cd","ce","cf"]
示例 2:
输入:digits = ""
输出:[]

class Solution {
List<String> result = new ArrayList<>();
public List<String> letterCombinations(String digits) {
if (digits == null || digits.length() == 0) {
return result;
}
String[] numString = {
"", "", "abc", "def",
"ghi", "jkl", "mno",
"pqrs", "tuv", "wxyz"};
backTracking(digits, numString, 0);
return result;
}
StringBuilder temp = new StringBuilder();
public void backTracking(String digits, String[] numString, int num) {
//遍历全部一次记录一次得到的字符串
if (num == digits.length()) {
result.add(temp.toString());
return;
}
String str = numString[digits.charAt(num) - '0'];
for (int i = 0; i < str.length(); i++) {
temp.append(str.charAt(i));
backTracking(digits, numString, num + 1);
temp.deleteCharAt(temp.length() - 1);
}
}
}