# 项目需求:解析出所有城市名称https://www.aqistudy.cn/historydata/if __name__ == "__main__": # headers = { # 'User-Agent':'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_12_0) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/73.0.3683.103 Safari/537.36' # } # url = 'https://www.aqistudy.cn/historydata/' # page_text = requests.get(url=url,headers=headers).text # # tree = etree.HTML(page_text) # host_li_list = tree.xpath('//div[@class="bottom"]/ul/li') # all_city_names = [] # #解析到了热门城市的城市名称 # for li in host_li_list: # hot_city_name = li.xpath('./a/text()')[0] # all_city_names.append(hot_city_name) # # #解析的是全部城市的名称 # city_names_list = tree.xpath('//div[@class="bottom"]/ul/div[2]/li') # for li in city_names_list: # city_name = li.xpath('./a/text()')[0] # all_city_names.append(city_name) # # print(all_city_names,len(all_city_names)) headers = { 'User-Agent': 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_12_0) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/73.0.3683.103 Safari/537.36' } url = 'https://www.aqistudy.cn/historydata/' page_text = requests.get(url=url, headers=headers).text tree = etree.HTML(page_text) # 解析到热门城市和所有城市对应的a标签 # //div[@class="bottom"]/ul/li/ 热门城市a标签的层级关系 # //div[@class="bottom"]/ul/div[2]/li/a 全部城市a标签的层级关系 a_list = tree.xpath('//div[@class="bottom"]/ul/li/a | //div[@class="bottom"]/ul/div[2]/li/a') all_city_names = [] for a in a_list: city_name = a.xpath('./text()')[0] all_city_names.append(city_name) print(all_city_names, len(all_city_names))