# 项目需求:解析出所有城市名称https://www.aqistudy.cn/historydata/
if __name__ == "__main__":
# headers = {
# 'User-Agent':'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_12_0) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/73.0.3683.103 Safari/537.36'
# }
# url = 'https://www.aqistudy.cn/historydata/'
# page_text = requests.get(url=url,headers=headers).text
#
# tree = etree.HTML(page_text)
# host_li_list = tree.xpath('//div[@class="bottom"]/ul/li')
# all_city_names = []
# #解析到了热门城市的城市名称
# for li in host_li_list:
# hot_city_name = li.xpath('./a/text()')[0]
# all_city_names.append(hot_city_name)
#
# #解析的是全部城市的名称
# city_names_list = tree.xpath('//div[@class="bottom"]/ul/div[2]/li')
# for li in city_names_list:
# city_name = li.xpath('./a/text()')[0]
# all_city_names.append(city_name)
#
# print(all_city_names,len(all_city_names))
headers = {
'User-Agent': 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_12_0) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/73.0.3683.103 Safari/537.36'
}
url = 'https://www.aqistudy.cn/historydata/'
page_text = requests.get(url=url, headers=headers).text
tree = etree.HTML(page_text)
# 解析到热门城市和所有城市对应的a标签
# //div[@class="bottom"]/ul/li/ 热门城市a标签的层级关系
# //div[@class="bottom"]/ul/div[2]/li/a 全部城市a标签的层级关系
a_list = tree.xpath('//div[@class="bottom"]/ul/li/a | //div[@class="bottom"]/ul/div[2]/li/a')
all_city_names = []
for a in a_list:
city_name = a.xpath('./text()')[0]
all_city_names.append(city_name)
print(all_city_names, len(all_city_names))