要求

可以根据文字很容易获取到span这个元素，那么如何再根据这个元素，获取到最外层的div元素呢？
也就是要往外跨5层。

实现

下面的代码直接摘抄过来，仅作为参考。

from playwright import sync_playwright
with sync_playwright() as p:
    for browser_type in [p.chromium, p.firefox, p.webkit]:
        browser = browser_type.launch(headless=False)
        page = browser.newPage()
        page.goto('https://duckduckgo.com/')
        element = page.querySelector('input[id=\"search_form_input_homepage\"]')
        parent = element.querySelector('xpath=..')
        grandparent = element.querySelector('xpath=../..')
        siblings = element.querySelectorAll('xpath=following-sibling::*')
        children = element.querySelectorAll('xpath=child::*')
        browser.close()

参考

In Playwright for Python, how do I get elements relative to ElementHandle (children, parent, grandparent, siblings)?