大家都知道斐波那契数列,现在要求输入一个整数n,请你输出斐波那契数列的第n项(从0开始,第0项为0,第1项是1)。
n<=39
public class Solution {public int Fibonacci(int n) {if(n == 0) return 0;if(n == 1) return 1;return Fibonacci(n-1)+Fibonacci(n-2);}}
public class Solution {public int Fibonacci(int n) {if(n < 2) return n;int[] res = new int[n +1];res[0] = 0;res[1] = 1;for(int i= 2; i <= n; i++){res[i] = res[i - 1] + res[i - 2];}return res[n];}}
public class Solution {public int Fibonacci(int n) {if(n < 2) return n;int[] dp = new int[3];dp[0] = 0;dp[1] = 1;for(int i = 2; i <= n; i++) {dp[i%3] = dp[(i-1)%3] + dp[(i-2)%3];}return dp[n%3];}}
