大家都知道斐波那契数列,现在要求输入一个整数n,请你输出斐波那契数列的第n项(从0开始,第0项为0,第1项是1)。
    n<=39

    1. public class Solution {
    2. public int Fibonacci(int n) {
    3. if(n == 0) return 0;
    4. if(n == 1) return 1;
    5. return Fibonacci(n-1)+Fibonacci(n-2);
    6. }
    7. }
    1. public class Solution {
    2. public int Fibonacci(int n) {
    3. if(n < 2) return n;
    4. int[] res = new int[n +1];
    5. res[0] = 0;
    6. res[1] = 1;
    7. for(int i= 2; i <= n; i++){
    8. res[i] = res[i - 1] + res[i - 2];
    9. }
    10. return res[n];
    11. }
    12. }
    1. public class Solution {
    2. public int Fibonacci(int n) {
    3. if(n < 2) return n;
    4. int[] dp = new int[3];
    5. dp[0] = 0;
    6. dp[1] = 1;
    7. for(int i = 2; i <= n; i++) {
    8. dp[i%3] = dp[(i-1)%3] + dp[(i-2)%3];
    9. }
    10. return dp[n%3];
    11. }
    12. }