1. #include <iostream>
    2. using namespace std;
    4. int main(){
    5.     const int numsToCalculate = 5;
    6.     cout << "This program will calculate " << numsToCalculate << "Fibonacci Numbers at a time" << endl;
    8.     long long num1 = 0;
    9.     long long num2 = 1;
    10.     char wantMore = '\0';
    11.     cout << num1 << " " << num2 << " ";
    13.     do
    14.     {
    15.         for (int counter = 0; counter < numsToCalculate; ++counter)
    16.         {
    17.             cout << num1 + num2 << " ";
    18.             long long num2Temp = num2;
    19.             num2 = num1 + num2;
    20.             num1 = num2Temp;
    21.         }
    23.         cout << endl << "Do you wanna more number ? (y/n)?";
    24.         cin >> wantMore;
    25.     }while (wantMore == 'y');
    27.     cout << "You are out the circulans" << endl;
    28.     return 0;
    29. }

    因为num1,num2数量超过int之后会变为负数，故这里使用long long