和传统 CRUD 一样,实现对员工信息的增删改查。
1.搭建环境
2.准备实体类
实体类:
package com.atguigu.rest.bean;/*** @author Dxkstart* @create 2021-11-09-18:58*/public class Employee {private Integer id;private String lastName;private String email;//1 male, 0 femaleprivate Integer gender;public Integer getId() {return id;}public void setId(Integer id) {this.id = id;}public String getLastName() {return lastName;}public void setLastName(String lastName) {this.lastName = lastName;}public String getEmail() {return email;}public void setEmail(String email) {this.email = email;}public Integer getGender() {return gender;}public void setGender(Integer gender) {this.gender = gender;}public Employee(Integer id, String lastName, String email, Integergender) {super();this.id = id;this.lastName = lastName;this.email = email;this.gender = gender;}public Employee() {}}
<br />3.准备到模拟数据
dao(里面包含crud方法):
package com.atguigu.rest.dao;
import com.atguigu.rest.bean.Employee;
import org.springframework.stereotype.Repository;
import java.util.Collection;
import java.util.HashMap;
import java.util.Map;
/**
* @author Dxkstart
* @create 2021-11-09-19:00
*/
@Repository
public class EmployeeDao {
private static Map<Integer, Employee> employees = null;
static {
employees = new HashMap<Integer, Employee>();
employees.put(1001, new Employee(1001, "E-AA", "aa@163.com", 1));
employees.put(1002, new Employee(1002, "E-BB", "bb@163.com", 1));
employees.put(1003, new Employee(1003, "E-CC", "cc@163.com", 0));
employees.put(1004, new Employee(1004, "E-DD", "dd@163.com", 0));
employees.put(1005, new Employee(1005, "E-EE", "ee@163.com", 1));
}
private static Integer initId = 1006;
//添加、修改
public void save(Employee employee) {
if (employee.getId() == null) {
employee.setId(initId++);
}
employees.put(employee.getId(), employee);
}
//查询所有员工信息
public Collection<Employee> getAll() {
return employees.values();
}
public Employee get(Integer id) {
return employees.get(id);
}
public void delete(Integer id) {
employees.remove(id);
}
}
