删除emp_no重复的记录,只保留最小的id对应的记录。
CREATE TABLE IF NOT EXISTS titles_test (id int(11) not null primary key,emp_no int(11) NOT NULL,title varchar(50) NOT NULL,from_date date NOT NULL,to_date date DEFAULT NULL);insert into titles_test values ('1', '10001', 'Senior Engineer', '1986-06-26', '9999-01-01'),('2', '10002', 'Staff', '1996-08-03', '9999-01-01'),('3', '10003', 'Senior Engineer', '1995-12-03', '9999-01-01'),('4', '10004', 'Senior Engineer', '1995-12-03', '9999-01-01'),('5', '10001', 'Senior Engineer', '1986-06-26', '9999-01-01'),('6', '10002', 'Staff', '1996-08-03', '9999-01-01'),('7', '10003', 'Senior Engineer', '1995-12-03', '9999-01-01');
删除后titles_test表为
| id | emp_no | title | from_date | to_date |
|---|---|---|---|---|
| 1 | 10001 | Senior Engineer | 1986-06-26 | 9999-01-01 |
| 2 | 10002 | Staff | 1996-08-03 | 9999-01-01 |
| 3 | 10003 | Senior Engineer | 1995-12-03 | 9999-01-01 |
| 4 | 10004 | Senior Engineer | 1995-12-03 | 9999-01-01 |
思路:
删除
DELETE FROM titles_test
where
删除重复emp_no
用 GROUP BY 和 MIN() 选出每个 emp_no 分组中最小的 id
delete from titles_testwhere id not in( select min(id) from titles_testgroup by emp_no)
