删除emp_no重复的记录,只保留最小的id对应的记录。

    1. CREATE TABLE IF NOT EXISTS titles_test (
    2. id int(11) not null primary key,
    3. emp_no int(11) NOT NULL,
    4. title varchar(50) NOT NULL,
    5. from_date date NOT NULL,
    6. to_date date DEFAULT NULL);
    7. insert into titles_test values ('1', '10001', 'Senior Engineer', '1986-06-26', '9999-01-01'),
    8. ('2', '10002', 'Staff', '1996-08-03', '9999-01-01'),
    9. ('3', '10003', 'Senior Engineer', '1995-12-03', '9999-01-01'),
    10. ('4', '10004', 'Senior Engineer', '1995-12-03', '9999-01-01'),
    11. ('5', '10001', 'Senior Engineer', '1986-06-26', '9999-01-01'),
    12. ('6', '10002', 'Staff', '1996-08-03', '9999-01-01'),
    13. ('7', '10003', 'Senior Engineer', '1995-12-03', '9999-01-01');

    删除后titles_test表为

    id emp_no title from_date to_date
    1 10001 Senior Engineer 1986-06-26 9999-01-01
    2 10002 Staff 1996-08-03 9999-01-01
    3 10003 Senior Engineer 1995-12-03 9999-01-01
    4 10004 Senior Engineer 1995-12-03 9999-01-01

    思路:
    删除
    DELETE FROM titles_test
    where
    删除重复emp_no
    用 GROUP BY 和 MIN() 选出每个 emp_no 分组中最小的 id

    1. delete from titles_test
    2. where id not in
    3. ( select min(id) from titles_test
    4. group by emp_no)