剑指 Offer 22. 链表中倒数第k个节点
快慢指针法
fast 先走 k 步,随后 fast 与 head 一起走,直到 fast 为空时,返回 head
class Solution {public ListNode getKthFromEnd(ListNode head, int k) {ListNode fast = head;for (int i = 0; i < k; i++) {fast = fast.next;}while (fast != null) {fast = fast.next;head = head.next;}return head;}}
