1. 遍历数据到object内(需要对数据的次数进行计算),并找出最大值
    2. 遍历最大值,一次把object的数据放进去
      1. https://jsbin.com/gufuhogode/edit?js,console ```javascript const countSort = (a) => { const object = {}, result = []; let max; a.forEach(n => { if (!max && max !== 0) { max = n; } else if (n > max) { max = n; } object[n] = !object[n] ? 1 : object[n] += 1; }); for(let i = 0; i <= max; i += 1) { const count = object[i]; if (count) { for(let j = 1; j <= count; j += 1) {
        1. result.push(i)
        } } } return result; }

    console.log(‘——————‘, countSort([2, 1, 3, 1, 4]))

    console.log(‘————‘, countSort([1,2,9,4,10,20,12])) // // // // [1, 2, 4, 9, 10, 12, 20] console.log(‘————‘, countSort([11,2,39,24,1,2,9])) // // // // [1, 2, 2, 9, 11, 24, 39] console.log(‘————‘, countSort([]))

    // // // // [] console.log(‘————‘, countSort([1,1,1,1,1])) ```