作业讲解

  1. 写段代码。计算 1-100 之积 ```python res = 1 for i in range(1,101): res = res*i

print(res)

  2. 2. 数学中斐波那契数列0， 1，1，2，3，5，初始值为0，1，后面每个值都为前面两个数之和，求100以内符合条件的斐波那契数列;
  4. 100个斐波那契数列
  5. ```python
  6. a,b = 0,1
  7. for i in range(100):
  8.     print(a, end=',')
  9.     a,b=b,b+a
  1. a,b = 0,1
  2. while True:
  3.     if a > 100:
  4.         break
  5.     print(a,end=',')
  6.     a,b = b, a+b
  1. 数字 121，数字从左往右看与从右往左看 值相等，我们称这个数字为回文数，比如121，131， 写段程序，判断某个数字是否为回文数。
  1. a = input("请输入数字：")
  3. if a == a[::-1]:
  4.     print(f'{a} == {a[::-1]}, {a}是回文数')
  5. else:
  6.     print(f'{a} !== {a[::-1]}, {a} 不是回文数')
  1. 写段程序，打印九九乘法表
    1. for x in range(1,10):
    2.  for y in range(x):
    3.      print(f'{y+1}*{x}={(y+1)*x}',end='\t')
    4.  print()
    打印金子塔结构
    1. for x in range(1,11):
    2.  print(' '*(11-(x+1)) + ((2*x)-1) * '*')
    ```python
    1.   *
    2.  ***
    3. *****
  1. ```python
  2. # s = "*".center(19)
  3. # print(s)
  4. for i in range(10):
  5.     count = 2*10-1
  6.     f = "*"* (2*(i+1)-1)
  7.     s = f.center(count)
  8.     print(s)
  1. 设计程序，提示用户输入月份1-12, 根据用户输入的数字，打印对应的季节，比如用户输入2，打印出春季.
    1. month = input('请输入月份：')
    2. if month in ['1','2','3']:
    3.  print('春季')
    4. elif month in ['4','5','6']:
    5.  print('夏季')
    6. elif month in ['7','8','9']:
    7.  print('秋季')
    8. elif month in ['10','11','12']:
    9.  print('冬季')
    10. else:
    11.  print('输入有误')

continue

表示继续从头开始，

与break跳出循环不一样

  1. for x in range(10):
  2.     print(f'x={x}')
  3.     if x == 3 or x == 6:
  4.         break
  1. x=0
  2. x=1
  3. x=2
  4. x=3

遇到continue 的时候，会从开始循环处继续循环，不会中断循环，但是continue下面的语句不再执行；
image.png

  1. for x in range(10):
  2.     print(f'before: x={x}')
  3.     if x == 3 or x == 6:
  4.         continue
  5.     print(f'end: x={x}')
  1. before: x=0
  2. end: x=0
  3. before: x=1
  4. end: x=1
  5. before: x=2
  6. end: x=2
  7. before: x=3
  8. before: x=4
  9. end: x=4
  10. before: x=5
  11. end: x=5
  12. before: x=6
  13. before: x=7
  14. end: x=7
  15. before: x=8
  16. end: x=8
  17. before: x=9
  18. end: x=9
  20. Process finished with exit code 0
  1. couter = 0
  2. while couter < 10:
  3.     couter += 1
  4.     if couter % 2 == 0:
  5.         continue
  6.     print(couter)