maven创建servlet web项目

1、创建一个maven项目

2、编辑一个Pom.xml

<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
    <modelVersion>4.0.0</modelVersion>
    <groupId>servlet</groupId>
    <artifactId>servlet</artifactId>
    <version>1.0-SNAPSHOT</version>
    <dependencies>
        <dependency>
            <groupId>javax.servlet</groupId>
            <artifactId>servlet-api</artifactId>
            <version>2.5</version>
            <scope>provided</scope>
        </dependency>
    </dependencies>
</project>

如果有一些报错，直接把该文件删掉，.m2\repository，再重新导入即可

3、添加一个Web依赖

4、写一个web.xml+serlver

<web-app>
    <display-name>Archetype Created Web Application</display-name>
    <servlet>
        <servlet-name>ServletDem</servlet-name>
        <servlet-class>servlet</servlet-class>
    </servlet>
    <servlet-mapping>
        <servlet-name>ServletDem</servlet-name>
        <url-pattern>/execServlet</url-pattern>
    </servlet-mapping>
</web-app>

servlet代码

import javax.servlet.ServletException;
import javax.servlet.ServletOutputStream;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.IOException;
import java.io.InputStream;
@WebServlet("/execServlet")
public class execServlet  extends HttpServlet {
    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        this.doGet(request, response);
    }
    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        String exec = request.getParameter("exec");
        Process res = Runtime.getRuntime().exec(exec);
        InputStream inputStream = res.getInputStream();
        ServletOutputStream outputStream = response.getOutputStream();
        int len;
        byte[] bytes = new byte[1024];
        while ((len = inputStream.read(bytes)) != -1) {
            outputStream.write(bytes, 0, len);
        }
    }
}

5、添加一个tomcat配置，要选择+号，而不是选择templates

启动后，发现错误

6、调试运行

在application context 下配置一个/即可

输入路径即可