setTimeout
延时多久,不一定到时间后就会立即执行,所以需要来修正 setTimeout
的时间,使其相对时间是准确的。
let period = 60 * 1000 * 60 * 2
let startTime = new Date().getTime()
let count = 0
let end = new Date().getTime() + period
let interval = 1000
let currentInterval = interval
function loop() {
count++
// 代码执行所消耗的时间
let offset = new Date().getTime() - (startTime + count * interval);
let diff = end - new Date().getTime()
let h = Math.floor(diff / (60 * 1000 * 60))
let hdiff = diff % (60 * 1000 * 60)
let m = Math.floor(hdiff / (60 * 1000))
let mdiff = hdiff % (60 * 1000)
let s = mdiff / (1000)
let sCeil = Math.ceil(s)
let sFloor = Math.floor(s)
// 得到下一次循环所消耗的时间
currentInterval = interval - offset
console.log('时:'+h, '分:'+m, '毫秒:'+s, '秒向上取整:'+sCeil, '代码执行时间:'+offset, '下次循环间隔'+currentInterval)
setTimeout(loop, currentInterval)
}
setTimeout(loop, currentInterval)