给你一个有效的 IPv4 地址 address,返回这个 IP 地址的无效化版本。
所谓无效化 IP 地址,其实就是用 “[.]” 代替了每个 “.”。
示例 1:
输入:address = "1.1.1.1"输出:"1[.]1[.]1[.]1"
示例 2:
输入:address = "255.100.50.0"输出:"255[.]100[.]50[.]0"
提示:
- 给出的 address 是一个有效的 IPv4 地址
方案一
var defangIPaddr = function (address) {return address.split('.').join('[.]')};let address = "1.1.1.1"console.log('执行前:' + address);console.log('执行后:' + defangIPaddr(address));
方案二
var defangIPaddr = function (address) {return address.replace(/\./g,"[.]");};let address = "1.1.1.1"console.log('执行前:' + address);console.log('执行后:' + defangIPaddr(address));
方案三
var defangIPaddr = function (address) {let newString = []for (let i = 0; i < address.length; i++) {if (address[i] === '.') {newString.push('[' + address[i] + ']')} else {newString.push(address[i])}}return newString.join('')};let address = "1.1.1.1"console.log('执行前:' + address);console.log('执行后:' + defangIPaddr(address));
