1. 统计100-999之间有多少个数字个位，十位，百位上的数字相加=15

for i in range(100,1000):
bai = i//100
shi =i//10%10
ge = i%10
if bai+shi+ge == 15:
print(i)

2. 有1,2,3,4 四个数字，能组成多少个互相不相同且无重复数字的三位数，分别都是多少？

count =0
for a in range(1,5):
for b in range(1, 5):
if a == b:
continue
else:
for c in range(1, 5):
if ac or bc:
continue
else:
print(a,b,c,sep=’’)
count +=1
print(‘总计’,count)

3. 输入1个3位的正整数，判断这个数是否为水仙花数（每一位上数字的立方和等于这个数本身，比如：153=53+33+1**3

while True:
num=input(‘请输入3位正整数’)
if num.isdigit():
if len(num) == 3:
i=int(num)
bai = i//100
shi =i//10%10
ge = i%10
if bai3+shi3+ge**3 ==i:
print(i,’是水仙花数’)
else:
print(i,’不是水仙花数’)
else:
print(‘请输出3位整数’)
elif num == ‘q’:
break
else:
print(‘请输入数字’)

4.例子3:将字符串’asd%&dasDFGH@#$%^&123435DFGH$%&*’中的特殊符号去除

str = ‘asd%&dasDFGH@#$%^&123435DFGH$%&‘
str1 = ‘!@#$%^&?<>:”‘
str2 =list()
for i in str:
if i in str1:
continue
else:
str2.append(i)
str3 = ‘’.join(str2)
print(str3,type(str3))

5. 查找每个want单词在字符串stri中的位置，

stri=’Everyone have a dream. Someone may want to be rich, someone may want to be beautiful, and someone may want to have power.’
i=stri.find(‘want’)
print(i)
i=stri.find(‘want’,i+1)
print(i)
i=stri.find(‘want’,i+1)
print(i)
i=stri.find(‘want’,i+1)
print(i)

i = 0
while True:
if i != -1 :
i = stri.find(‘want’, i)
print(i)
i = stri.find(‘want’, i+1)
else:
False

6.对下列列表进行处理：

stuInfo=[
[1001,’Kate’,185,’Female’,[70,90,98]],
[1002,’Mike’,165,’Male’,[75,90,100,50,98]],
[1003,’John’,170,’Male’,[100,88,98,76]]
]

场景1. 支持性别查询操作，输入’Female’，统计女生有多少个？输入’Male’,统计男生有多少个，支持反复统计

while True:
str = input(“请输入性别:”)
m=0
count =0
while mi = stuInfo[m][3]
if i==str:
count+=1
m +=1
else:
m += 1
print(count)

场景2：对该stuinfo学生信息，使用while编写代码统计有多少个学生成绩平均分超过90分

list= stuInfo[0][4]

print(list)

sum = sum(list)

print(sum)@Time : 2022/8/23 18:23

@Author : Andrew

1. 统计100-999之间有多少个数字个位，十位，百位上的数字相加=15

for i in range(100,1000):
bai = i//100
shi =i//10%10
ge = i%10
if bai+shi+ge == 15:
print(i)

2. 有1,2,3,4 四个数字，能组成多少个互相不相同且无重复数字的三位数，分别都是多少？

count =0
for a in range(1,5):
for b in range(1, 5):
if a == b:
continue
else:
for c in range(1, 5):
if ac or bc:
continue
else:
print(a,b,c,sep=’’)
count +=1
print(‘总计’,count)

3. 输入1个3位的正整数，判断这个数是否为水仙花数（每一位上数字的立方和等于这个数本身，比如：153=53+33+1**3

while True:
num=input(‘请输入3位正整数’)
if num.isdigit():
if len(num) == 3:
i=int(num)
bai = i//100
shi =i//10%10
ge = i%10
if bai3+shi3+ge**3 ==i:
print(i,’是水仙花数’)
else:
print(i,’不是水仙花数’)
else:
print(‘请输出3位整数’)
elif num == ‘q’:
break
else:
print(‘请输入数字’)

4.例子3:将字符串’asd%&dasDFGH@#$%^&123435DFGH$%&*’中的特殊符号去除

str = ‘asd%&dasDFGH@#$%^&123435DFGH$%&‘
str1 = ‘!@#$%^&?<>:”‘
str2 =list()
for i in str:
if i in str1:
continue
else:
str2.append(i)
str3 = ‘’.join(str2)
print(str3,type(str3))

5. 查找每个want单词在字符串stri中的位置，

stri=’Everyone have a dream. Someone may want to be rich, someone may want to be beautiful, and someone may want to have power.’
i=stri.find(‘want’)
print(i)
i=stri.find(‘want’,i+1)
print(i)
i=stri.find(‘want’,i+1)
print(i)
i=stri.find(‘want’,i+1)
print(i)

i = 0
while True:
if i != -1 :
i = stri.find(‘want’, i)
print(i)
i = stri.find(‘want’, i+1)
else:
False

6.对下列列表进行处理：

stuInfo=[
[1001,’Kate’,185,’Female’,[70,90,98]],
[1002,’Mike’,165,’Male’,[75,90,100,50,98]],
[1003,’John’,170,’Male’,[100,88,98,76]]
]

场景1. 支持性别查询操作，输入’Female’，统计女生有多少个？输入’Male’,统计男生有多少个，支持反复统计

while True:
str = input(“请输入性别:”)
m=0
count =0
while mi = stuInfo[m][3]
if i==str:
count+=1
m +=1
else:
m += 1
print(count)

场景2：对该stuinfo学生信息，使用while编写代码统计有多少个学生成绩平均分超过90分

list= stuInfo[0][4]

print(list)

sum = sum(list)

print(sum)

avgscore = sum/len(list)

m = 0
count =0
while mi = stuInfo[m][4]
avgscore =sum(i)/len(i)
if avgscore >90:
print(stuInfo[m][2],avgscore)
count +=1
m +=1
else:
m +=1
print(count)

avgscore = sum/len(list)

m = 0
count =0
while mi = stuInfo[m][4]
avgscore =sum(i)/len(i)
if avgscore >90:
print(stuInfo[m][2],avgscore)
count +=1
m +=1
else:
m +=1
print(count)