1、创建对象
var reg = /xinlang/;var str = 'xinlangasdfasdf';// 检验字符串是否匹配正则表达式,用testvar boo = reg.test(str);console.log('boo', boo); // true// 2.方式2: 使用构造函数方式创建正则对象var reg2 = new RegExp('zhanghuan');var str = 'asdfasdfzhanghuanasdfasdf';var boo2 = reg2.test(str);console.log('boo2', boo2); //// 3.正则表达式参数g-全局匹配,i-忽略大小写,m-多行匹配var reg3 = /zhanGsan/gi;// var reg3 = new RegExp('zhangsan','g');var str3 = '111111111zhangsan222222zhangsan333333zhangsan';var newStr3 = str3.replace(reg3, '张三');console.log('newStr3', newStr3);
2、常见匹配规则
var log = function() {var len = arguments.length;if (len === 1) {console.log(arguments[0])} else if (len === 2) {console.log(arguments[0], arguments[1]);} else {console.log(arguments[0], arguments[1], arguments[2]);}console.log('')}// 1. 任意字符 .var reg1 = /.../;var str1 = 'aa';console.log('boo1', reg1.test(str1)); // false// 2. \w 字母、数字、下划线var reg2 = /\w\w/;var str2 = 'as';console.log('boo2', reg2.test(str2)); // trueconsole.log('boo2', reg2.test('$a')); // false// 3. \s 任意空白字符var reg3 = /..\s../;console.log('boo3', reg3.test('aa bb')); // trueconsole.log('boo3', reg3.test('aa bb')); // true// 4. \d 匹配数字,等同于[0-9]var reg4 = /\d\d\d\d/;console.log('boo4', reg4.test('9999')); // true// 5. \D 匹配非数字,等同于\[^0-9]var reg5 = /\d\D\d/;console.log('boo5', reg5.test('233')); // falseconsole.log('boo5', reg5.test('2a3')); // true// 6. | 或匹配,如 /x|y/ 正则可匹配 x 或 y 两个字符var reg6 = /abc|xyz/;console.log('boo6', reg6.test('asdfasdfabcasdfasdf')); // trueconsole.log('boo6', reg6.test('asdfasdfxyzasdfasdf')); // true// 7. [xyz] 表示包含 xyz 里面的任意一个,相当于x|y|zvar reg7 = /[abc]/;log('boo7', reg7.test('aaa')); // truelog('boo7', reg7.test('ddd')); // false// [a-zA-Z] // 匹配所有的大小写字母var reg7 = /[a-zA-Z]/;var reg7 = /[0-9]/; // 匹配0到9,相当于\d// 8. [^x] 匹配除“x”之外的所有字符,其中“x”可以为任意字符var reg8 = /[^s]/;log('boo8', reg8.test('asdf')); // truelog('boo8', reg8.test('sss')); // false// 9. [^xyz] 同上,匹配除“x、y、z”之外的任意字符var reg9 = /[^abc]/; // 存在abc以外的字符都能匹配log('boo9', reg9.test('d')); // truelog('boo9', reg9.test('ab')); // false// 10. ^ 匹配字符串的开始var reg10 = /^[a-zA-Z]\w\w\w/; // 匹配:第一个字符是字母,紧跟三个字符(数字,字母或下划线)log('boo10', reg10.test('a_8al2k323')); // truelog('boo10', reg10.test('8a_8al2k323')); // falsevar reg10 = /^1\d\d\d\d\d\d\d\d\d\d$/; // 11位数字log('boo10', reg10.test('13811111111')); // truelog('boo10', reg10.test('23811111111')); // false// 11. \$ 匹配字符串的结束// 12. \x 转义字符var reg12 = /\.com/;log('boo12', reg12.test('acom')); // falselog('boo12', reg12.test('asdfasdf.com')); // true// '2021/05/05'var reg12 = /\d\d\d\d\/\d\d\/\d\d/;// 13. `?` 重复出现零次或一次var reg13 = /^https?/;console.log('boo13', reg13.test('http://asdfasdfasdf')); // trueconsole.log('boo13', reg13.test('https://asdfasdfasdf')); // true// 14. `+` 重复出现一次或多次var reg14 = /a+/; // 有一个a或者多个a都能匹配log('boo14', reg14.test('sdfsdfsaasdf')); // truelog('boo14', reg14.test('22222a')); // true// 15. `*` 重复出现零次或多次var reg15 = /^https?.*/;log('boo15', reg15.test('http://asdfasdfsadf')); // true// 16. {n} 重复出现 n 次var reg16 = /^1\d{10}$/;// 17. {n,} 至少重复出现 n 次var reg17 = /\d{10,}/; // 至少有10个数字// 18. {m,n} 重复重现 m 到 n 次,其中,m<nvar reg17 = /\d{10,20}/; // 匹配10个到20个数字
3、惰性匹配
var reg = /\d+/;var str = '23423424234234234';var arr = str.match(reg);console.log('arr', arr);var reg2 = /\d+?/;var arr2 = str.match(reg2);console.log('arr2', arr2);
4、分组
// 分组可以使用 \1-代表第一组, \2-第2组var dateReg1 = /^(\d{4})-(\d{2})-(\d{2})$/;var dateReg2 = /^(\d{4})-(\d{2})-\2$/; // \d{2} 和 \2 数字要一样var str = '2021-06-06';console.log('date1', dateReg1.test(str));console.log('date2', dateReg2.test(str));var phoneReg = /^(1\d{2})(\d{4})\2$/;var str = '13800000000';console.log('phone', phoneReg.test(str));// 字符串替换时,可以使用正则分组,使用$1-第1组,$2-表示第2组var str = '13811112222';var newStr = str.replace(/(\d{3})(\d{4})(\d{4})/, '$1****$3');console.log('newStr', newStr);
// 字面量的方式创建对象var obj = {a: 2,b: 3};// 构造函数方式创建对象,构造函数是用来创建对象var obj1 = new Object();obj1.name = 'zhangsan';// 字面量var arr = [1, 2, 3];// 构造函数var arr1 = new Array();arr1[0] = 1;arr1[1] = 2;
function add() {console.log(arguments[0], arguments[1]);}add(10, 20);var log = function() {var len = arguments.length;if (len === 1) {console.log(arguments[0])} else if (len === 2) {console.log(arguments[0], arguments[1]);} else {console.log(arguments[0], arguments[1], arguments[2]);}}log(1);log(1, 2);log(1, 2, 3);
