https://leetcode-cn.com/problems/search-in-rotated-sorted-array-ii/ 数组、二分查找
二分查找
function search(nums: number[], target: number): boolean {let l = 0;let r = nums.length - 1;while (l <= r) {let m = (l + r) >> 1;if (nums[m] === target) return true;// 这里是去重if (nums[m] === nums[l] && nums[m] === nums[r]) {l++;r--;} else if (nums[l] > nums[m]) {if (target > nums[m] && target <= nums[r]) {l = m + 1;} else {r = m - 1;}} else {if (target >= nums[l] && target < nums[m]) {r = m - 1;} else {l = m + 1;}}}return false;};
