给你两个 非空 的链表,表示两个非负的整数。它们每位数字都是按照 逆序 的方式存储的,并且每个节点只能存储 一位 数字。
请你将两个数相加,并以相同形式返回一个表示和的链表。
你可以假设除了数字 0 之外,这两个数都不会以 0 开头。
示例 1:
输入:l1 = [2,4,3], l2 = [5,6,4]
输出:[7,0,8]
解释:342 + 465 = 807.
示例 2:
输入:l1 = [0], l2 = [0]
输出:[0]
示例 3:
输入:l1 = [9,9,9,9,9,9,9], l2 = [9,9,9,9]
输出:[8,9,9,9,0,0,0,1]
package mainimport "fmt"type ListNode struct {Val intNext *ListNode}func main() {fmt.Println("2. 两数相加")l11 := &ListNode{Val: 3, Next: nil}l12 := &ListNode{Val: 4, Next: l11}l13 := &ListNode{Val: 2, Next: l12}l14 := &ListNode{Val: 9, Next: l13}printList(l14)l21 := &ListNode{Val: 4, Next: nil}l22 := &ListNode{Val: 6, Next: l21}l23 := &ListNode{Val: 5, Next: l22}printList(l23)res := addTwoNumbers(l14, l23)printList(res)}func printList(node *ListNode) {for node != nil {fmt.Print(" ", node.Val)node = node.Next}fmt.Println()}/*** Definition for singly-linked list.* type ListNode struct {* Val int* Next *ListNode* }*/func addTwoNumbers(l1 *ListNode, l2 *ListNode) *ListNode {carry := 0temp := &ListNode{}head := tempfor l1 != nil && l2 != nil {sum := l1.Val + l2.Val + carrynode := &ListNode{}node.Val = sum % 10carry = sum / 10temp.Next = nodetemp = nodel1 = l1.Nextl2 = l2.Next}for l1 != nil {sum := l1.Val + carrynode := &ListNode{}node.Val = sum % 10carry = sum / 10temp.Next = nodetemp = nodel1 = l1.Next}for l2 != nil {sum := l2.Val + carrynode := &ListNode{}node.Val = sum % 10carry = sum / 10temp.Next = nodetemp = nodel2 = l2.Next}if carry > 0 {node := &ListNode{}node.Val = carrytemp.Next = nodetemp = node}return head.Next}
