一、list操作分组、过滤、求和、最值、排序、去重。
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1、通过groupingBy可以分组指定字段
// 分组Map<String, List<User>> groupBySex = userList.stream().collect(Collectors.groupingBy(User::getSex));// 遍历分组for (Map.Entry<String, List<User>> entryUser : groupBySex.entrySet()) {String key = entryUser.getKey();List<User> entryUserList = entryUser.getValue();}
多字段分组
Function<WarehouseReceiptLineBatch, List<Object>> compositeKey = wlb ->Arrays.<Object>asList(wlb.getWarehouseReceiptLineId(), wlb.getWarehouseAreaId(), wlb.getWarehouseLocationId());Map<Object, List<WarehouseReceiptLineBatch>> map =warehouseReceiptLineBatchList.stream().collect(Collectors.groupingBy(compositeKey, Collectors.toList()));//遍历分组for (Map.Entry<Object, List<WarehouseReceiptLineBatch>> entryUser : map.entrySet()) {List<Object> key = (List<Object>) entryUser.getKey();List<WarehouseReceiptLineBatch> entryUserList = entryUser.getValue();Long warehouseReceiptLineId = (Long) key.get(0);Long warehouseAreaId = (Long) key.get(0);Long warehouseLocationId = (Long) key.get(0);}
2、过滤:通过filter方法可以过滤某些条件
// 过滤// 排除掉工号为201901的用户List<User> userCommonList = userList.stream().filter(a -> !a.getJobNumber().equals("201901")).collect(Collectors.toList());
3、求和:分基本类型和大数类型求和,基本类型先mapToInt,然后调用sum方法,大数类型使用reduce调用BigDecimal::add方法
// 求和// 基本类型int sumAge = userList.stream().mapToInt(User::getAge).sum();// BigDecimal求和BigDecimal totalQuantity = userList.stream().map(User::getFamilyMemberQuantity).reduce(BigDecimal.ZERO, BigDecimal::add);
上面的求和不能过滤bigDecimal对象为null的情况,可能会报空指针,这种情况,我们可以用filter方法过滤,或者重写求和方法
package com.vvvtimes.util;import java.math.BigDecimal;public class BigDecimalUtils {public static BigDecimal ifNullSet0(BigDecimal in) {if (in != null) {return in;}return BigDecimal.ZERO;}public static BigDecimal sum(BigDecimal ...in){BigDecimal result = BigDecimal.ZERO;for (int i = 0; i < in.length; i++){result = result.add(ifNullSet0(in[i]));}return result;}}
使用重写的方法
BigDecimal totalQuantity2 = userList.stream().map(User::getFamilyMemberQuantity).reduce(BigDecimal.ZERO, BigDecimalUtils::sum);
判断对象空
stream.filter(x -> x!=null)
stream.filter(Objects::nonNull)
判断字段空
stream.filter(x -> x.getDateTime()!=null)
4、最值
求最小与最大,使用min max方法
// 最小Date minEntryDate = userList.stream().map(User::getEntryDate).min(Date::compareTo).get();// 最大Date maxEntryDate = userList.stream().map(User::getEntryDate).max(Date::compareTo).get();
有时候我们需要知道最大最小对应的这个对象,我们可以通过如下方法获取
Comparator<LeasingBusinessContract> comparator = Comparator.comparing(LeasingBusinessContract::getLeaseEndDate);LeasingBusinessContract maxObject = leasingBusinessContractList.stream().max(comparator).get();
5、List 转map
/*** List -> Map* 需要注意的是:* toMap 如果集合对象有重复的key,会报错Duplicate key ....* user1,user2的id都为1。* 可以用 (k1,k2)->k1 来设置,如果有重复的key,则保留key1,舍弃key2*/Map<Long, User> userMap = userList.stream().collect(Collectors.toMap(User::getId, a -> a,(k1,k2)->k1));
list转map的时候有时候会将date类型作为key,实际情况中使用string的多,我们可以将某个字段转成string
Map<String, WorkCenterLoadVo> workCenterMap = list.stream().collect(Collectors.toMap(key->DateFormatUtils.format(key.getDate(), "yyyy-MM-dd"), a -> a,(k1,k2)->k1));
6、排序:可通过Sort对单字段多字段排序
// 排序// 单字段排序,根据id排序userList.sort(Comparator.comparing(User::getId));// 多字段排序,根据id,年龄排序userList.sort(Comparator.comparing(User::getId).thenComparing(User::getAge));
7、去重:可通过distinct方法进行去重
// 去重List<Long> idList = new ArrayList<Long>();idList.add(1L);idList.add(1L);idList.add(2L);List<Long> distinctIdList = idList.stream().distinct().collect(Collectors.toList());
针对属性去重
List<AddOutboundNoticeDetailsBatchVo> entryDetailsBatchDistinctBatchIdList = entryDetailsBatchList.stream().filter(distinctByKey(b -> b.getMaterialBatchNumberId())).collect(Collectors.toList());//distinctByKey自己定义public static <T> Predicate<T> distinctByKey(Function<? super T, Object> keyExtractor) {Map<Object, Boolean> seen = new ConcurrentHashMap<>();return t -> seen.putIfAbsent(keyExtractor.apply(t), Boolean.TRUE) == null;}
8、获取list某个字段组装新list
// 获取list对象的某个字段组装成新listList<Long> userIdList = userList.stream().map(a -> a.getId()).collect(Collectors.toList());
9、批量设置list列表字段为同一个值
addList.stream().forEach(a -> a.setDelFlag("0"));
10、不同实体的list拷贝
List<TimePeriodDate> timePeriodDateList1 = calendarModelVoList.stream().map(p->{TimePeriodDate e = new TimePeriodDate(); e.setStartDate(p.getBegin());e.setEndDate(p.getEnd()); return e;}).collect(Collectors.toList());
二、 map的多种循环方式
Map<String, String> map = new HashMap<String, String>();// 第一种遍历方式System.out.println("第一种遍历方式:通过遍历 Map 的 keySet,遍历 Key 和 Value");for (String key : map.keySet()) {System.out.println("Key: " + key + ", Value: " + map.get(key));}// 第二种遍历方式(如果在遍历过程中,有删除某些Key-Value的需求,可以使用这种遍历方式)System.out.println("\n第二种遍历方式:通过Iterator 迭代器遍历 Key 和 Value");Iterator<Map.Entry<String, String>> iterator = map.entrySet().iterator();while(iterator.hasNext()) {Map.Entry<String, String> entry = iterator.next();System.out.println("Key: " + entry.getKey() + ", Value: " + entry.getValue());}// 第三种遍历方式(推荐,尤其是容量大时)System.out.println("\n第三种遍历方式:通过遍历 Map 的 entrySet,遍历 Key 和 Value");for (Map.Entry<String, String> entry : map.entrySet()) {System.out.println("Key: " + entry.getKey() + ", Value: " + entry.getValue());}// 第四种遍历方式System.out.println("\n第四种遍历方式:通过遍历 Map 的 values,只能遍历 Value,获取不到对应的 Key");for (String value : map.values()) {System.out.println("Value: " + value);}// 第五种遍历方式(JDK 1.8支持的 Lambda 表达式,强烈推荐!!!)System.out.println("\n第五种遍历方式:通过 Lambda 表达式,遍历 Key 和 Value");map.forEach((key, value) -> {System.out.println("Key: " + key + ", Value: " + value);});
三、Optional解决判断Null为空的问题
orElse、orElseGet的用法相当于value值为null时,给予一个默认值:
当user值为null时,orElse函数依然会执行createUsers()方法,而orElseGet函数并不会执行createUsers()
User user = null;user = Optional.ofNullable(user).orElse(createUsers());user = Optional.ofNullable(user).orElseGet(() -> createUsers());public User createUsers(){User user = new User();user.setName("Test");return user;}
orElseThrow:当value值为null时,直接抛一个异常出去
User user = null;Optional.orNullable(user).orElseThrow(() -> new Exception("用户不存在"))
判断一个user不为空时,执行业务代码
Optional.ofNullable(user).ifPresent(u->{// TODO: do something});
取值某个对象属性的值
// 以前写法public String getCity(User user) throws Exception{if(user!=null){if(user.getAddress()!=null){Address address = user.getAddress();if(address.getCity()!=null){return address.getCity();}}}throw new Excpetion("取值错误");}// java8新写法public String getCity(User user) throws Exception{return Optional.ofNullable(user).map(u-> u.getAddress()).map(a->a.getCity()).orElseThrow(()->new Exception("取指错误"));}
