1、方法

• [x] //获取请求的URI

    `String requestURI = request.getRequestURI();  `<br />        `System.out.println(requestURI);`

  2、实现

  ```java package servlet;

import jakarta.servlet.ServletException; import jakarta.servlet.http.HttpServlet; import jakarta.servlet.http.HttpServletRequest; import jakarta.servlet.http.HttpServletResponse;

import java.io.IOException; import java.io.PrintWriter; import java.net.HttpCookie; import java.net.SocketTimeoutException;

/**

• @Author: 小雷学长
• @Date: 2022/3/20 - 17:22

• @Version: 1.8 */ public class RequestTestServlet extends HttpServlet {

  @Override protected void doGet(HttpServletRequest request, HttpServletResponse response)

       throws ServletException, IOException {
   //获取请求的URI
   String requestURI = request.getRequestURI();
   System.out.println(requestURI);
   response.setContentType("text/html");
   PrintWriter out = response.getWriter();
   out.print(requestURI);

  } } xml <?xml version=”1.0” encoding=”UTF-8”?>

  RequestTestServlet servlet.RequestTestServlet RequestTestServlet /testrequest

```