题目:输入某年某月某日,判断这一天是这一年的第几天?
程序分析:以3月5日为例,应该先把前两个月的加起来,然后再加上5天即本年的第几天,特殊情况,闰年且输入月份大于3时需考虑多加一天。
#include <stdio.h>
#include <stdlib.h>
int main(void)
{
int day, month, year,leap;
int sum = 0;
printf("\n请输入年,月,日,格式为:年,月,日 (2020,12,10)\n");//格式为:2021,2,18
scanf("%d,%d,%d", &year, &month, &day);
switch (month) //先计算某月以前月份的总天数
{
case 1:
sum = 0;
break;
case 2:
sum = 31;
break;
case 3:
sum = 59; //平年2月份28天
break;
case 4:
sum = 90;
break;
case 5:
sum = 120;
break;
case 6:
sum = 151;
break;
case 7:
sum = 181;
break;
case 8:
sum = 212;
break;
case 9:
sum = 243;
break;
case 10:
sum = 273;
break;
case 11:
sum = 304;
break;
case 12:
sum = 334;
break;
default:
printf("data error");
break;
}
sum = sum + day; //再加上某天的天数
if(year%400==0 || (year%4==0&&year%100!=0)){ //判断是不是闰年
leap = 1;
}else{
leap = 0;
}
if(leap==1&&month>2){ //如果是闰年且月份大于2,总天数应该加一天
sum++;
}
printf("这是这一年的第%d天\n", sum);
}