题目：https://pintia.cn/problem-sets/994805260223102976/problems/994805261217153024

测试点二，日常坑，有个空格，改成getline才行

代码

  1. #include<cctype>
  2. #include<cstdio>
  3. #include<iostream>
  4. #include<string>
  5. using namespace std;
  7. int main(){
  8.     int n;
  9.     string str;
  10.     scanf("%d", &n);
  11.     getchar();
  12.     for(int i = 0; i < n; i++){
  13.         bool s1 = false, s2 = false, s3 = false;//s1代表有非法字符，s2代表有字母，s3代表有数字
  14.         getline(cin, str);
  15.         if(str.size() < 6){
  16.             printf("Your password is tai duan le.\n");
  17.             continue;
  18.         }
  19.         for(int j = 0; j < str.size(); j++){
  20.             if(!(isalnum(str[j]) || str[j] == '.')){
  21.                 printf("Your password is tai luan le.\n");
  22.                 s1 = true;
  23.                 break;
  24.             } else {
  25.                 if(s2 == false && isalpha(str[j])) s2 = true;
  26.                 if(s3 == false && str[j] <= '9' && str[j] >= '0') s3 = true;
  27.             }
  28.         }
  29.         if(s1 == false && s2 == false) printf("Your password needs zi mu.\n");
  30.         else if(s1 == false && s3 == false) printf("Your password needs shu zi.\n");
  31.         else if(s1 == false && s2 && s3) printf("Your password is wan mei.\n");
  32.     }
  33. }