Question:
We have two special characters. The first character can be represented by one bit 0
. The second character can be represented by two bits (10
or 11
).
Now given a string represented by several bits. Return whether the last character must be a one-bit character or not. The given string will always end with a zero.
Example:
Input:
bits = [1, 0, 0]
Output: True
Explanation:
The only way to decode it is two-bit character and one-bit character.
So the last character is one-bit character.
Input:
bits = [1, 1, 1, 0]
Output: False
Explanation:
The only way to decode it is two-bit character and two-bit character.
So the last character is NOT one-bit character.
Solution:
/**
* @param {number[]} bits
* @return {boolean}
*/
var isOneBitCharacter = function(bits) {
let ones = 0;
for (let i = bits.length - 2; i >= 0 && bits[i] !== 0; i--) {
ones++;
}
if (ones % 2 > 0) return false;
return true;
};