- conding=utf_8
list=[]
i=0
for i in range(0,3):
list.append(input(“append插入:”))
list.insert(i,input(“insert插入:”))
print(f”{i},list[i]值{list[i]},list的长度为{len(list)},{list}”)
list.remove(list[i])#根据值删除1
del list[i-1]#根据下标删除i+1
print(f”删除后的长度为{len(list)}”)
list[i+1]=”a+1”
print(f”不保存排序后的list{sorted(list)},原list{list}”)
index=list.index(“a+1”)
print(f”{list[index]}的坐标为{index}”)
list.sort(reverse=True)#降序并保存到原集合
bprint(f”降序后的集合{list}”)
String 没写 原因没时间">字典
stu={“name”:”liu”,”age”:”26”,”sex”:”男”}
print(f”stu的key{stu.keys},stu的value{stu.values()}”)
stu[“height”]=”180”
print(f”显示身高{stu.get(‘height’)}”)
for i in stu :
print(i)
del stu[“height”]
print(stu.items())
String 没写 原因没时间- 99
for i in range(1,10):
for k in range (1,i+1):
print(f”{i}{k}={ik}”,end=” “)
print(“”)
conding=utf_8
list=[]
i=0
for i in range(0,3):
list.append(input(“append插入:”))
list.insert(i,input(“insert插入:”))
print(f”{i},list[i]值{list[i]},list的长度为{len(list)},{list}”)
list.remove(list[i])#根据值删除1
del list[i-1]#根据下标删除i+1
print(f”删除后的长度为{len(list)}”)
list[i+1]=”a+1”
print(f”不保存排序后的list{sorted(list)},原list{list}”)
index=list.index(“a+1”)
print(f”{list[index]}的坐标为{index}”)
list.sort(reverse=True)#降序并保存到原集合
bprint(f”降序后的集合{list}”)

字典
stu={“name”:”liu”,”age”:”26”,”sex”:”男”}
print(f”stu的key{stu.keys},stu的value{stu.values()}”)
stu[“height”]=”180”
print(f”显示身高{stu.get(‘height’)}”)
for i in stu :
print(i)
del stu[“height”]
print(stu.items())

String 没写 原因没时间
99
for i in range(1,10):
for k in range (1,i+1):
print(f”{i}{k}={ik}”,end=” “)
print(“”)

names=[‘a’,’b’,’c’,’d’,’e’,’f’,’g’,’h’,’i’]
offices=[[],[],[]]
for i in range (0,len(names)):
index = random.randint(0,len(names)-1);
print(index)
cls=random.randint(0,2)
print(cls)
offices[cls].append(names[index])
del names[index]
print(offices)
for i in range (len(offices)):
for k in range (len(offices[i])):
while len(offices[i])>3:
if i==0:
offices[i+1].append(offices[i][k])
del offices[i][k]
elif i==1 :
offices[i + 1].append(offices[i][k])
del offices[i][k]
elif i==2:
if len(offices[0])<3:
offices[0].append(offices[i][k])
del offices[i][k]
else :
offices[1].append(offices[i][k])
del offices[i][k]
print(offices)
