categories: leetcode
题目描述
At a lemonade stand, each lemonade costs $5
.
Customers are standing in a queue to buy from you, and order one at a time (in the order specified by bills
).
Each customer will only buy one lemonade and pay with either a $5
, $10
, or $20
bill. You must provide the correct change to each customer, so that the net transaction is that the customer pays $5.
Note that you don’t have any change in hand at first.
Return true
if and only if you can provide every customer with correct change.
Example 1:
Input: [5,5,5,10,20]
Output: true
Explanation:
From the first 3 customers, we collect three $5 bills in order.
From the fourth customer, we collect a $10 bill and give back a $5.
From the fifth customer, we give a $10 bill and a $5 bill.
Since all customers got correct change, we output true.Example 2:
Input: [5,5,10]
Output: trueExample 3:
Input: [10,10]
Output: falseExample 4:
Input: [5,5,10,10,20]
Output: false
Explanation:
From the first two customers in order, we collect two $5 bills.
For the next two customers in order, we collect a $10 bill and give back a $5 bill.
For the last customer, we can’t give change of $15 back because we only have two $10 bills.
Since not every customer received correct change, the answer is false.
Note:
class Solution {
public boolean lemonadeChange(int[] bills) {
if (bills[0] != 5) {//若第一个不是5,则返回false
return false;
}
else {
int five = 1,ten = 0;
int length = bills.length;
for(int i = 1;i < length;i++) {//从第二个数据开始
if(bills[i] == 5) {
five++;
}
else if(bills[i] == 10){
if(five == 0) {
return false;
}
else {//进行相应的加减
five--;
ten++;
}
}
else {
if(five == 0) {
return false;
}
else if(ten != 0) {//10、5的情况
five--;
ten--;
}
else {
if(five >= 3) {//5,5,5的情况
five -= 3;
}
else {
return false;
}
}
}
}
}
return true;
}
}
思路及总结
感觉这个题目没有体现所谓贪心算法的思想,只是一些if else的语句,以及需要考虑一些边界问题。