/* * @lc app=leetcode.cn id=46 lang=javascript * * [46] 全排列 */const backtrack = (list, temp, nums) => { // 终止条件 if (temp.length === nums.length) { list.push([...temp]); return } for (let i = 0; i < nums.length; i++) { if (temp.includes(nums[i])) { continue } /** * 放入一个 * 执行递推公式 * 弹出一个 */ temp.push(nums[i]) backtrack(list, temp, nums) temp.pop() }}// @lc code=start/** * @param {number[]} nums * @return {number[][]} */var permute = function (nums) { const list = [] backtrack(list, [], nums) return list};