题目描述
/已知折半查找的部分代码如下,勿改动。请补充实现折半查找算法Bin_Search。
要求:实现方式为递归方法。
/
include
using namespace std;
using namespace std;
const int MaxSize=100; //顺序表的最大长度
//有序表类
class LinearSearch{
public:
LinearSearch(){n=0;}
~LinearSearch(){}
void Insert(int x);//有序表的插入,使序列仍有序
void DispList(); //输出表
int Bin_Search(int key); //调用下面的递归算法
int Bin_Search(int low, int high, int key); //递归算法,成功返回位置,否则返回0
private:
int r[MaxSize+1]; //存储元素(r[1]~r[n]存储元素)
int n; //顺序表实际长度
};
//在有序表中插入元素x,使序列仍有序
void LinearSearch::Insert(int x){
int i;
if (n>=MaxSize) //表满不能插入
throw “Overflow”;
r[0]=x;
for(i=n;r[i]>x;i—)
r[i+1]=r[i];//将i位置元素后移
r[i+1]=x; //在位置i+1插入元素x
n++; //线性表长度增1
}
void LinearSearch::DispList() //输出表
{
int i;
cout<<”Data:”;
for(i=1;i<=n;i++)
{
cout<
cout<
//在下面补充实现折半查找算法(两个函数Bin_Search,1个形参和3个形参的各一个)
int main(){
LinearSearch A; //空表A
int x,key;
//利用插入函数创建有序表,以0结束
while(1){
cin>>x;
if(!x)break;
try{
A.Insert(x);
}
catch(char *wrong){
cout<
}
A.DispList();
int pos;
cin>>key;
pos=A.Bin_Search(key);
if(!pos)//查找失败
cout<<”Find “<
}
输入
输出
样例输入
43 53 1 25 2 426 324 345 423 34 0 43
样例输出
Data:1 2 25 34 43 53 324 345 423 426
Find 43 success,position:5
提示
来源
提交
import java.util.Scanner;class LinearSearch{int n = 0;int[] r;int MaxSize = 100;public LinearSearch() {r = new int[MaxSize];}void insert(int x) throws Exception {int i;if (n>MaxSize) //表满不能插入throw new Exception("Overflow");r[0]=x;for(i=n;r[i]>x;i--)r[i+1]=r[i];//将i位置元素后移r[i+1]=x;//在位置i+1插入元素xn++;//线性表长度增1}void DispList(){System.out.print("Data:");for (int i = 1; i <= n; i++) {System.out.print(r[i]+" ");}System.out.println();}int Bin_Search(int key){return Bin_Search(1,n,key);}int Bin_Search(int low,int high,int key){if(low>high)return -1;int mid = (low + high) >> 1;if(r[mid] > key)return Bin_Search(low, mid - 1, key);else if(r[mid] < key)return Bin_Search(mid + 1, high, key);return mid;}}public class Main {public static void main(String[] args) throws Exception {LinearSearch linearSearch = new LinearSearch();Scanner scanner = new Scanner(System.in);int key;while(true){int x = scanner.nextInt();if(x == 0)break;linearSearch.insert(x);}key = scanner.nextInt();linearSearch.DispList();int pos = linearSearch.Bin_Search(key);if(pos!=-1){System.out.println("Find "+key+" success,position:"+pos);}else{System.out.println("Find "+key+" failure");}}}
