#! /usr/bin/env python
#coding:utf-8
class Node:
"""
二叉树左右枝
"""
def __init__(self, data):
"""
节点结构
"""
self.left = None
self.right = None
self.data = data
def insert(self, data):
"""
插入节点数据
"""
if data < self.data:
if self.left is None:
self.left = Node(data)
else:
self.left.insert(data)
elif data > self.data:
if self.right is None:
self.right = Node(data)
else:
self.right.insert(data)
def lookup(self, data, parent=None):
"""
遍历二叉树
"""
if data < self.data:
if self.left is None:
return None, None
return self.left.lookup(data, self)
elif data > self.data:
if self.right is None:
return None, None
return self.right.lookup(data, self)
else:
return self, parent
def delete(self, data):
"""
删除节点
"""
node, parent = self.lookup(data) #已有节点
if node is not None:
children_count = node.children_count() #判断子节点数
if children_count == 0:
# 如果该节点下没有子节点,即可删除
if parent.left is node:
parent.left = None
else:
parent.right = None
del node
elif children_count == 1:
# 如果有一个子节点,则让子节点上移替换该节点(该节点消失)
if node.left:
n = node.left
else:
n = node.right
if parent:
if parent.left is node:
parent.left = n
else:
parent.right = n
del node
else:
# 如果有两个子节点,则要判断节点下所有叶子
parent = node
successor = node.right
while successor.left:
parent = successor
successor = successor.left
node.data = successor.data
if parent.left == successor:
parent.left = successor.right
else:
parent.right = successor.right
def compare_trees(self, node):
"""
比较两棵树
"""
if node is None:
return False
if self.data != node.data:
return False
res = True
if self.left is None:
if node.left:
return False
else:
res = self.left.compare_trees(node.left)
if res is False:
return False
if self.right is None:
if node.right:
return False
else:
res = self.right.compare_trees(node.right)
return res
def print_tree(self):
"""
按顺序打印数的内容
"""
if self.left:
self.left.print_tree()
print self.data,
if self.right:
self.right.print_tree()
def tree_data(self):
"""
二叉树数据结构
"""
stack = []
node = self
while stack or node:
if node:
stack.append(node)
node = node.left
else:
node = stack.pop()
yield node.data
node = node.right
def children_count(self):
"""
子节点个数
"""
cnt = 0
if self.left:
cnt += 1
if self.right:
cnt += 1
return cnt