剑指 Offer 29. 顺时针打印矩阵

难度简单214
输入一个矩阵，按照从外向里以顺时针的顺序依次打印出每一个数字。

示例 1：
输入：matrix = [[1,2,3],[4,5,6],[7,8,9]]
输出：[1,2,3,6,9,8,7,4,5]

示例 2：
输入：matrix = [[1,2,3,4],[5,6,7,8],[9,10,11,12]]
输出：[1,2,3,4,8,12,11,10,9,5,6,7]


限制：

  • 0 <= matrix.length <= 100
  • 0 <= matrix[i].length <= 100
    1. class Solution:
    2.   def spiralOrder(self, matrix: List[List[int]]) -> List[int]:
    3.       res = []
    4.       while matrix:
    5.           res += matrix.pop(0)
    6.           matrix = list(zip(*matrix))[::-1]
    7.       return res
    zip()函数参考：https://www.runoob.com/python3/python3-func-zip.html